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Vilka [71]
3 years ago
6

Which days are part of line BE?

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
8 0

Answer:

B) Rays AB and AE

Step-by-step explanation:

Though A-F, A-D, and A-C all meet at one point on line B-E, point A, they aren't a <em>part</em> of it. Point A on line B-E marks the "midpoint" of it, and therefore, ray A-E and A-B are part of line B-E.

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19. Which of the following
Andrew [12]

9514 1404 393

Answer:

  b. angle K is acute

Step-by-step explanation:

We're often told not to draw any conclusions from the appearance of a figure in a geometry problem. Here, angle K appears to be somewhat less than 90°, so angle K is acute.

__

<em>Additional comment</em>

This choice of answer is confirmed by the fact that the other two (visible) choices say the same thing. If one of them is correct, so is the other one. Hence they must both be incorrect. (An obtuse angle is more than 90°.)

4 0
3 years ago
Please give me a full solution: Chuck has 9 colored beans: 6 blue beans, one green, one red and one yellow. He wants to arrange
Musya8 [376]

Answer: 56ways

Step-by-step explanation:

given data:

total beans = 9

blue beans = 6

red beans = 1

yellow beans = 1

green beans = 1

solution:

This is a permutation problem because there is a condition attached to it which states that the beans most be arranged in a way that atleast each none blue has a blue bean on its side when shared.

= ( r + n - 1 ! ) / r ! ( n - 1 )!

= 3 + 6 - 1 / 3! ( 6-1 )!

= 8! / 3! x 5!

= 40320/ 720

= 56 ways

4 0
3 years ago
Solve 5x-y=5 and 2y-x^2=11 without using trial improvement
iren2701 [21]

Answer:

x = 7, y = 30  and  x = 3, y = 10

Step-by-step explanation:

5x - y = 5, then y = 5x - 5

2y - x^2 = 11

2(5x - 5) - x^2 = 11

10x - 10 - x^2 = 11

-x^2 + 10x -10 = 11

-x^2 + 10x -21 = 0

x^2 - 10x + 21 = 0

(x - 7)(x - 3) = 0

x = 7, y = 30

x = 3, y = 10

8 0
3 years ago
Simplify 1- cos^2 Θ / cos^2 Θ<br><br> Answers<br><br> sin2 θ<br><br> cos2 θ<br><br> tan2 θ<br><br> 1
Tems11 [23]

Answer:

<h3><u /></h3>

<u>Trigonometric identities</u>

<u />

\large \begin{aligned}\cos^2 \theta + \sin^2 \theta & = 1\\\implies \quad \quad \sin^2 \theta & = 1 - \cos^2 \theta\\\\\tan \theta=\dfrac{\sin \theta}{\cos \theta} \end{aligned}

Therefore, using the <u>identities</u>, the given expression can be <em>simplified</em> as follows:

\large\begin{aligned}\implies \dfrac{1- \cos^2 \theta}{\cos^2 \theta} & = \dfrac{\sin^2 \theta}{\cos^2 \theta}\\\\& = \tan^2 \theta\end{aligned}

3 0
2 years ago
Read 2 more answers
Which is a y-intercept of the graphed function​
AfilCa [17]

Well, a y-intercept is a the point on a graph where the x value equals 0, because the point sits exactly on the y-axis. In this case, the y-intercept would be (0, -9).

5 0
3 years ago
Read 2 more answers
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