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yan [13]
3 years ago
13

I need help on this one.

Mathematics
1 answer:
Firlakuza [10]3 years ago
3 0

Answer: 1/3

Step-by-step explanation:

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If P(x) = 12x3 + 11x2 - 9x + 10 and<br> Q(x) = 4x2 – 3x + 2, find<br> P(x) + Q(x)
aniked [119]

Answer:

12x^3+15x^2-12x+12

Step-by-step explanation:

P(x) = 12x^3 + 11x^2 - 9x + 10

Q(x) = 4x^2 – 3x + 2

P(x) + Q(x) = 12x^3 + 11x^2 - 9x + 10+ 4x^2 – 3x + 2

Combine like terms

                 =12x^3+11x^2+4x^2-9x-3x+10+2

                  =12x^3+15x^2-12x+12

4 0
3 years ago
The aquarium is 24 inches long and 10 inches wide.The volume of the aquarium is 2,880 cubic inches. How many inches tall is the
bazaltina [42]
The answer is 12 inches tall.
   
 If you multiply 24 x 10 you will get 240.

Then divide 2,880 (Total) by 240 (Product of 10x24) and you get 12.
 
To check, you will normally multiply 24 x 10 x 12 which will equal 2,880.  
6 0
2 years ago
Read 2 more answers
For this exponential function,
Archy [21]

Replace x with 3 and solve:

10 x 5^3

Simplify:

10 x 125 = 1250

Answer: y = 1250

7 0
2 years ago
Calculus graph please help
tresset_1 [31]

Answer:

See Below.

Step-by-step explanation:

We are given the graph of <em>y</em> = f'(x) and we want to determine the characteristics of f(x).

Part A)

<em>f</em> is increasing whenever <em>f'</em> is positive and decreasing whenever <em>f'</em> is negative.

Hence, <em>f</em> is increasing for the interval:

(-\infty, -2) \cup (-1, 1)\cup (3, \infty)

And <em>f</em> is decreasing for the interval:

\displaystyle (-2, -1) \cup (1, 3)

Part B)

<em>f</em> has a relative maximum at <em>x</em> = <em>c</em> if <em>f'</em> turns from positive to negative at <em>c</em> and a relative minimum if <em>f'</em> turns from negative to positive to negative at <em>c</em>.

<em>f'</em> turns from positive to negative at <em>x</em> = -2 and <em>x</em> = 1.

And <em>f'</em> turns from negative to positive at <em>x</em> = -1 and <em>x</em> = 3.

Hence, <em>f</em> has relative maximums at <em>x</em> = -2 and <em>x</em> = 1, and relative minimums at <em>x</em> = -1 and <em>x</em> = 3.

Part C)

<em>f</em> is concave up whenever <em>f''</em> is positive and concave down whenever <em>f''</em> is negative.

In other words, <em>f</em> is concave up whenever <em>f'</em> is increasing and concave down whenever <em>f'</em> is decreasing.

Hence, <em>f</em> is concave up for the interval (rounded to the nearest tenths):

\displaystyle (-1.5 , 0) \cup (2.2, \infty)

And concave down for the interval:

\displaystyle (-\infty, -1.5) \cup (0, 2.2)

Part D)

Points of inflections are where the concavity changes: that is, <em>f''</em> changes from either positive to negative or negative to positive.

In other words, <em>f </em>has an inflection point wherever <em>f'</em> has an extremum point.

<em>f'</em> has extrema at (approximately) <em>x</em> = -1.5, 0, and 2.2.

Hence, <em>f</em> has inflection points at <em>x</em> = -1.5, 0, and 2.2.

7 0
2 years ago
A cylinder and cone have the same height and radius. The height of each is 5 cm, and the radius is 2 cm.
Vlad [161]

Answer:

12rhehrhehrhjnehrhrhehrhehehrrhrjejejej

6 0
3 years ago
Read 2 more answers
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