Answer:
103= p small
plarge = 123
Step-by-step explanation:
We know that the the ratio of the areas is the scale factor squared/
Larger triangle over smaller triangle
72
----- = scale factor ^2
50
simplify by dividing by 2 on top and bottom
36
----- = scale factor ^2
25
Take the square root of each side
sqrt(36)
-------------- = sqrt(scale factor ^2)
sqrt(25)
6
-------------- = scale factor
5
The ratio of the perimeters is the scale factor
p large 6
-------------- = ----------------
p small 5
Using cross products
6 p large = 5 p small
We know the sum is 226
p large + p small = 226
p large = 226 - p small
We have 2 equation and 2 unknowns
6 p large = 5 p small
Substitute for p large
6 (226 - p small) = 5 p small
1356 - 6 p small = 5 p small
Add 6 p small to each side
1356 = 11 p small
divide by 11
1356/11 = p small
P large = 226-1356/11
p large = 2486/11-1356/11
plarge = 1130/11
The solution requires whole number answers so
1356/11 = p small
123.27 which rounds to 123
plarge = 1130/11
plarge = 102.7272 = 103
You should first change the denominator into same number, which is 18
So you multiply the first fraction of both numerator and denominator by 3, and the second by 2:
3(g-2) / 18 - 2(g+3) / 18 = (3g - 6 - 2g - 6) / 18 = (g-12)/18
Answer:
480 cubic cm.
Step-by-step explanation:
We have been given that a wedge of cheese in he shape of a triangular prism has lengths of 10 cm, 13 cm, and 13 cm for its triangular sides. The perpendicular distance from the 10 cm side to the point of the wedge is 12 cm. The height of the wedge is 8 cm.
We can see from our attachment that base of our triangular face is 10 cm and height of the triangular face is 12 cm and height of wedge is 8 cm.
Substituting these values in volume formula we will get,
Therefore, the volume of cheese wedge will be 480 cubic cm.
