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FinnZ [79.3K]
3 years ago
9

Tell whether the rates form a proportion.

Mathematics
1 answer:
pav-90 [236]3 years ago
5 0

Answer: no

Step-by-step explanation: the answer is no

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What is the solution of X +8 over 5 x minus one less then 0
Anna35 [415]
X < -3. Subtract one from both sides and you get x + 8 over 5 is less than 1. Multiple both sides by 5 and you get x + 8 is less than 5. Finally, subtract 8 from both sides and you get x is less than -3.
6 0
3 years ago
Harper has $15.00 to spend at her grocery store. She is going to buy bags of fruit that cost $4.75 each and one box of crackers
Andrej [43]
First write the inequality:    15\leq4.75x +3.50

Then to solve, first subtract 3.50 from both sides to get:

11.50\leq4.75x

Then divide by 4.75 to get 2.42, and since you can't buy .42 of a bag  of fruit, you round down. So your final answer would be 2 bags of fruit.
7 0
3 years ago
Read 2 more answers
What amount of money will accumulate to $192,400 in 6 years and 11 months at the interest rate of 5.36% compounded semi-annually
MaRussiya [10]

We will have the following:

\begin{gathered} 192400=A(1+\frac{0.0536}{2})^{(11/12)(2)}\Rightarrow A=\frac{192400}{(1+0.0536/2)^{(11/12)(2)}} \\  \\ \Rightarrow A=183293.7505...\Rightarrow A\approx18329375 \end{gathered}

So, the original quantity was approximately $183 293.75.

3 0
1 year ago
PLS SOLVE THIS<br> I WILL MARK BRAINLIEST
Paraphin [41]

Answer:

AB = 25 units

Step-by-step explanation:

In right triangle ACB, CD\perp AB

Therefore, by geometric mean property:

CD^{2} ={AD\times DB}  \\  \\  {10}^{2}  = AD\times 5 \\  \\ 100 = 5AD \\  \\  AD =  \frac{100}{5}  \\  \\ AD = 20

AB = AD + DB

AB = 20 + 5

AB = 25 units

3 0
3 years ago
Triangle ABC is labeled with points A(5, 2), B(1, 2) and C(3, 6) on a coordinate plane. Find the coordinates of A' B' C' after a
Ilia_Sergeevich [38]

Answer:

After reflection over the x-axis, we have the coordinates as follows;

A’ (5,-2)

B’ ( 1,-2)

C’ (3,-6)

Step-by-step explanation:

Here, we want to find the coordinates A’ B’ and C’ after a reflection over the x-axis

By reflecting over the x-axis, the y-coordinate is bound to change in sign

So if we have a Point (x,y) and we reflect over the x-axis, the image of the point after reflection would turn to (x,-y)

We simply go on to negate the value of the y-coordinate

Mathematically if we apply these to the given points, what we get are the following;

A’ (5,-2)

B’ ( 1,-2)

C’ (3,-6)

4 0
3 years ago
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