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Leto [7]
2 years ago
10

Can anybody help me with my homework please. and explain me how to got the answer. Thanks

Mathematics
1 answer:
natka813 [3]2 years ago
8 0

In the problems A-F, You multiply each of the numbers by itself.  Like 9²=9×9=81

3³=3×3×3=27     6³=6×6×6=216 and so on for the other problems

G-I  is 36=6²  100=10² and so on the cube is the same except you multiply the number three times by itself.  I hope this helped a bit. Just ask if you still don't understand.

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Brandon mows the neighbor's yard to earn extra
olganol [36]

Answer:

7 is the answer you're looking for

5 0
2 years ago
A= (4,5) B= (7,-9) what is AB ?
VMariaS [17]
If you are needing to find the distance between the two points, you must use a simple formula, cleverly named, the distance formula. Since I can't input special characters into the answer box, I'll explain it the best I can.

( The square root of (  (x - x)^2 + (y - y)^2 )  )

First, we need to find the first x subtracted from the second x, as so:
(4,5) and (7,-9)

4 - 7 = -3

Now, we square the -3.

-3^2 = 
-3 * -3 = 9

Next, we have to find the first y subtracted from the second y.
(4,5) and (7,-9)

5 - (-9) = 14

Now, we square the 14.

14^2 =
14 * 14 = 196

Let's see how the numbers fit in the formula:

sqrt((x - x)^2 + (y - y)^2)

sqrt((4 - 7)^2 + (7 - (-9))^2)

sqrt((-3)^2 + (14)^2)

sqrt( 9 + 196 )

This is where we currently are in the formula, all we have to do now is square root the total of 9 + 196.

sqrt( 9 + 196 )
sqrt( 205 )

The square root of 205 = 14.31782106...

There are a few answers you can consider:

1) sqrt(205)
2) 14.32 units
or
3) 14.31782106

Depending on the answer you desire, use the one that sounds the most correct to you. Although all three are correct, it may not be the answer you require. 

Hope I could help! If my math is incorrect, or I provided answers you were not looking for, please let know! However, if my answer is correct and well explained, please consider marking my answer as <em>Brainliest</em>! :)

Have a good one.
God bless!
4 0
3 years ago
Please help due in 6 minutes!!!!
luda_lava [24]

Answer:

hi

Step-by-step explanation:

Sorry u gonna fail cause I to dumb.

4 0
3 years ago
given examples of relations that have the following properties 1) relexive in some set A and symmetric but not transitive 2) equ
rodikova [14]

Answer: 1) R = {(a, a), (а,b), (b, a), (b, b), (с, с), (b, с), (с, b)}.

It is clearly not transitive since (a, b) ∈ R and (b, c) ∈ R whilst (a, c) ¢ R. On the other hand, it is reflexive since (x, x) ∈ R for all cases of x: x = a, x = b, and x = c. Likewise, it is symmetric since (а, b) ∈ R and (b, а) ∈ R and (b, с) ∈ R and (c, b) ∈ R.

2) Let S=Z and define R = {(x,y) |x and y have the same parity}

i.e., x and y are either both even or both odd.

The parity relation is an equivalence relation.

a. For any x ∈ Z, x has the same parity as itself, so (x,x) ∈ R.

b. If (x,y) ∈ R, x and y have the same parity, so (y,x) ∈ R.

c. If (x.y) ∈ R, and (y,z) ∈ R, then x and z have the same parity as y, so they have the same parity as each other (if y is odd, both x and z are odd; if y is even, both x and z are even), thus (x,z)∈ R.

3) A reflexive relation is a serial relation but the converse is not true. So, for number 3, a relation that is reflexive but not transitive would also be serial but not transitive, so the relation provided in (1) satisfies this condition.

Step-by-step explanation:

1) By definition,

a) R, a relation in a set X, is reflexive if and only if ∀x∈X, xRx ---> xRx.

That is, x works at the same place of x.

b) R is symmetric if and only if ∀x,y ∈ X, xRy ---> yRx

That is if x works at the same place y, then y works at the same place for x.

c) R is transitive if and only if ∀x,y,z ∈ X, xRy∧yRz ---> xRz

That is, if x works at the same place for y and y works at the same place for z, then x works at the same place for z.

2) An equivalence relation on a set S, is a relation on S which is reflexive, symmetric and transitive.

3) A reflexive relation is a serial relation but the converse is not true. So, for number 3, a relation that is reflexive but not transitive would also be serial and not transitive.

QED!

6 0
3 years ago
After mixing two types of candies, the price became $3.40 per lb. The quantity of the first type of candy was 5/12 of the quanti
drek231 [11]

Answer:

$2.90

Step-by-step explanation:

The quantity of the 1st type of candy be x lb and that of the second type − y lb with the price of $ p/lb.

Then, x=5y/12 or y=2.4x.

The "total price" equation will be: 4.6x + 2.4xp = 3.4(x+2.4x).  

Solving for p, we get p = $2.90.

5 0
3 years ago
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