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3 years ago

What else would need to be congruent to show that triangle ABC is congruent to triangle DEF by ASA?

Mathematics

2 answers:

svet-max [94.6K]3 years ago

8 0

ASA

answer
D. m<B = m<E

MAXImum [283]3 years ago

7 0

Answer:

Option D. ∠B ≅ ∠E

Step-by-step explanation:

In ΔABC and ΔDEF,

Measure of side AB = Measure of side DE = 10 units

∠A ≅ ∠ D ≅ 45°

Now we have to prove ΔABC ≅ ΔDEF by the property of congruence ASA.

Since one angle and one side are equal.

So other angle based on sides AB and DE will be the adjacent angles ∠B and ∠E

Therefore, Option D. ∠B ≅ ∠E will be the answer.

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An observer took a time-exposure photograph of polaris and five nearby stars. how many hours were required to show their star pa

olga55 [171]

Photographing stars requires you to keep your exposure open for a long time. Taking pictures of star trails would take about 30 minutes to three hours. If you multiply that for the 6 stars stated above in the problem then you would be needing that much time if the stars were close and approximately 3 to 18 hours capture their star trails if they were far apart from each other.

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3 years ago

What is the answer to -4|8n|=-32

Kisachek [45]

Answer:

n=-1, 1

Step-by-step explanation:

-4|8n|=-32

Divide each side by -4

-4|8n|/-4=-32/-4

|8n|=8

When we have absolute values, we need to make two equations, one positive and one negative

8n=8 8n=-8

Divide each side by 8

8n/8 = 8/8 8n/8 = -8/8

n=1 n=-1

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3 years ago

Bfjsbsuevehhhshdbdhdhd

Ivenika [448]

Answer:

wasafsfawdasffdgdfsdf

Step-by-step explanation:

4 0

3 years ago

(PRECALC) I need help on this one plz ❤️❤️❤️ help a girl out & the favor will be returned

tia_tia [17]

Answer:

The coordinates of the P' point are (-17.3,-10).

Step-by-step explanation:

We can use the components of the vector from 0 to P point. We know that the diameter is 40 meters, so the magnitude of the vector will be 20 m.

Now, the angle from the negative x-direction to the vector is 210°-180° = 30°.

The x-component of the vector will be:

$V_{x}=-Vcos(30)$

$V_{x}=-20cos(30)=-17.32\: m$

It is negative because the component is in the negative x-direction.

The y-component of the vector will be:

$V_{y}=-Vsin(30)$

$V_{y}=-20sin(30)=-10\: m$

It is negative too because the component is in the negative y-direction.

Therefore, the coordinates of the P' point are P'(-17.3,-10)

I hope it helps you!

7 0

3 years ago

write an equation of the line perpendicular to the given line that contains P in point slope form? P (4,-4) y=1/3x+4

11Alexandr11 [23.1K]

Answer: $y+4=-3(x-4)$

Step-by-step explanation:

- The equation of the line in point-slope form is:

$y-y_1=m(x-x_1)$

Where m is the slope and $(x_1,y_1)$ is a point of the line.

- The equation of the line $y=\frac{1}{3}x+4$ is written is slope-intercept form, where the slope is $\frac{1}{3}$ .

- By definition, when two lines are perpendicular to each other, the slopes are the negative reciprocals. Therefore, the slope of the perpendicular line must be -3.

- Substitute the point P and the slope -3 into the equation in point-slope form, therefore, you obtain:

$y+4=-3(x-4)$

4 0

3 years ago