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agasfer [191]
3 years ago
7

Can somebody help I’ll give brainless plss

Mathematics
2 answers:
Ymorist [56]3 years ago
4 0

Answer:

93.22

Step-by-step explanation:

Find the amount of the tip

79*18%

79 * .18

14.22

Add this to the amount of the bill

79+14.22

93.22

Anestetic [448]3 years ago
3 0

Answer:

$93.22

Step-by-step explanation:

bill = $79

tip = 18%

tip amount = tip % of bill

=18/100 * $79

=$1422/100

=$14.22

total cost = $79 + $14.22

=$93.22

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Answer:

B. (4,-3)

Step-by-step explanation:

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Q^2-4q-21=0 solve the equation
kobusy [5.1K]

q= 7 or q= -3


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3 years ago
A grower believes that one in five of his citrus trees are infected with the citrus red mite. How large a sample should be taken
mihalych1998 [28]

Answer:

n=6147

Step-by-step explanation:

1) Notation and definitions

X=1 number of citrus trees that are infected with the citrus red mite.

n=5 random sample taken

\hat p=\frac{1}{5}=0.2 estimated proportion of citrus trees that are infected with the citrus red mite.

p true population proportion of citrus trees that are infected with the citrus red mite.

Me=0.01 represent the margin of error desired

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The population proportion have the following distribution

p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})

In order to find the critical values we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical values would be given by:

t_{\alpha/2}=-1.96, t_{1-\alpha/2}=1.96

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.01 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.2(1-0.2)}{(\frac{0.01}{1.96})^2}=6146.56  

And rounded up we have that n=6147

5 0
4 years ago
Please solve asap i need help
aleksandr82 [10.1K]

Answer:

7 degrees, Because the entire triangle has to add up to a 180 degree triangle

Step-by-step explanation:

3 0
3 years ago
According to an​ almanac, 70​% of adult smokers started smoking before turning 18 years old. ​(a) if 200 adult smokers are rando
Strike441 [17]

Solution: ​(a) if 200 adult smokers are randomly​ selected, how many would we expect to have started smoking before turning 18 years​ old?

Answer: It is expected that in a random sample of 200 adult smokers, 0.70 (200)=140 will have started smoking before turning 18.

​(b) would it be unusual to observe 160 smokers who started smoking before turning 18 years old in a random sample of 200 adult​ smokers? why?

Answer: Yes, it would be unusual to observe 160 smokers who started smoking before turning 18 years old in a random sample of 200 adult​ smokers, because 160 is greater than μ + 2σ

3 0
3 years ago
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