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STatiana [176]
3 years ago
15

According to an​ almanac, 70​% of adult smokers started smoking before turning 18 years old. ​(a) if 200 adult smokers are rando

mly​ selected, how many would we expect to have started smoking before turning 18 years​ old? ​(b) would it be unusual to observe 160 smokers who started smoking before turning 18 years old in a random sample of 200 adult​ smokers? why?
Mathematics
1 answer:
Strike441 [17]3 years ago
3 0

Solution: ​(a) if 200 adult smokers are randomly​ selected, how many would we expect to have started smoking before turning 18 years​ old?

Answer: It is expected that in a random sample of 200 adult smokers, 0.70 (200)=140 will have started smoking before turning 18.

​(b) would it be unusual to observe 160 smokers who started smoking before turning 18 years old in a random sample of 200 adult​ smokers? why?

Answer: Yes, it would be unusual to observe 160 smokers who started smoking before turning 18 years old in a random sample of 200 adult​ smokers, because 160 is greater than μ + 2σ

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Answer:

y=−2x−9

Step-by-step explanation:

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2 years ago
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∆ABC has vertices A(–2, 0), B(0, 8), and C(4, 2)
Natali [406]

Answer:

Part 1) The equation of the perpendicular bisector side AB is y=-\frac{1}{4}x+\frac{15}{4}

Part 2) The equation of the perpendicular bisector side BC is y=\frac{2}{3}x+\frac{11}{3}

Part 3) The equation of the perpendicular bisector side AC is y=-3x+4

Part 4) The coordinates of the point P(0.091,3.727)

Step-by-step explanation:

Part 1) Find the equation of the perpendicular bisector side AB

we have

A(–2, 0), B(0, 8)

<em>step 1</em>

Find the slope AB

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute the values

m=\frac{8-0}{0+2}

m=4

<em>step 2</em>

Find the slope of the perpendicular line to side AB

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

therefore

The slope is equal to

m=-\frac{1}{4}

<em>step 3</em>

Find the midpoint AB

The formula to calculate the midpoint between two points is equal to

M(\frac{x1+x2}{2},\frac{y1+y2}{2})

substitute the values

M(\frac{-2+0}{2},\frac{0+8}{2})

M(-1,4)

<em>step 4</em>

Find the equation of the perpendicular bisectors of AB

the slope is m=-\frac{1}{4}

passes through the point (-1,4)

The equation in slope intercept form is equal to

y=mx+b

substitute

4=(-\frac{1}{4})(-1)+b

solve for b

b=4-\frac{1}{4}

b=\frac{15}{4}

so

y=-\frac{1}{4}x+\frac{15}{4}

Part 2) Find the equation of the perpendicular bisector side BC

we have

B(0, 8) and C(4, 2)

<em>step 1</em>

Find the slope BC

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute the values

m=\frac{2-8}{4-0}

m=-\frac{3}{2}

<em>step 2</em>

Find the slope of the perpendicular line to side BC

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

therefore

The slope is equal to

m=\frac{2}{3}

<em>step 3</em>

Find the midpoint BC

The formula to calculate the midpoint between two points is equal to

M(\frac{x1+x2}{2},\frac{y1+y2}{2})

substitute the values

M(\frac{0+4}{2},\frac{8+2}{2})

M(2,5)

<em>step 4</em>

Find the equation of the perpendicular bisectors of BC

the slope is m=\frac{2}{3}

passes through the point (2,5)

The equation in slope intercept form is equal to

y=mx+b

substitute

5=(\frac{2}{3})(2)+b

solve for b

b=5-\frac{4}{3}

b=\frac{11}{3}

so

y=\frac{2}{3}x+\frac{11}{3}

Part 3) Find the equation of the perpendicular bisector side AC

we have

A(–2, 0) and C(4, 2)

<em>step 1</em>

Find the slope AC

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

substitute the values

m=\frac{2-0}{4+2}

m=\frac{1}{3}

<em>step 2</em>

Find the slope of the perpendicular line to side AC

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

therefore

The slope is equal to

m=-3

<em>step 3</em>

Find the midpoint AC

The formula to calculate the midpoint between two points is equal to

M(\frac{x1+x2}{2},\frac{y1+y2}{2})

substitute the values

M(\frac{-2+4}{2},\frac{0+2}{2})

M(1,1)        

<em>step 4</em>

Find the equation of the perpendicular bisectors of AC

the slope is m=-3

passes through the point (1,1)

The equation in slope intercept form is equal to

y=mx+b

substitute

1=(-3)(1)+b

solve for b

b=1+3

b=4

so

y=-3x+4

Part 4) Find the coordinates of the point of concurrency of the perpendicular bisectors (P)

we know that

The point of concurrency of the perpendicular bisectors is called the circumcenter.

Solve by graphing

using a graphing tool

the point of concurrency of the perpendicular bisectors is P(0.091,3.727)

see the attached figure

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