The percentage of eighth-graders that chose History as their favorite subject is 19%
<h3>Percentages and proportion</h3>
From the given table, we have the following parameters
Total students in the 8th grade = 124 students
Total number of 8th graders that chose history = 11 + 12
Total number of 8th graders that chose history = 23
Required percentage = 23/124 * 100
Required percentage = 19%
Hence the percentage of eighth-graders that chose History as their favorite subject is 19%
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Answer: The attachment is blank
Step-by-step explanation: :/
Answer:
To find out the number coming from each school, you need to use the proportion of the school's population out of the population of all three.
Total population = 618 + 378 + 204
= 1,200 students
North Middle school:
= 618/1,200 * 20
= 10 students
Central Middle School:
= 378 / 1,200 * 20
= 6 students
South Middle School:
= 204/1,200 * 20
= 4 students
<h3>
Answer:</h3>
System
Solution
- p = m = 5 — 5 lb peanuts and 5 lb mixture
<h3>
Step-by-step explanation:</h3>
(a) Generally, the equations of interest are one that models the total amount of mixture, and one that models the amount of one of the constituents (or the ratio of constituents). Here, there are two constituents and we are given the desired ratio, so three different equations are possible describing the constituents of the mix.
For the total amount of mix:
... p + m = 10
For the quantity of peanuts in the mix:
... p + 0.2m = 0.6·10
For the quantity of almonds in the mix:
... 0.8m = 0.4·10
For the ratio of peanuts to almonds:
... (p +0.2m)/(0.8m) = 0.60/0.40
Any two (2) of these four (4) equations will serve as a system of equations that can be used to solve for the desired quantities. I like the third one because it is a "one-step" equation.
So, your system of equations could be ...
___
(b) Dividing the second equation by 0.8 gives
... m = 5
Using the first equation to find p, we have ...
... p + 5 = 10
... p = 5
5 lb of peanuts and 5 lb of mixture are required.
