Answer:
bro there should be a value or a final answer of the question then only we can find the value
Step-by-step explanation:
hope it helps you
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<u>500,000 + 80,000 + 2,000 + 90 + 4</u>. EXPANDED FORM ✔
<u>Five hundred eighty-two thousand, ninety-four
</u>. WORD FORM ✔
<u>Step-by-step explanation</u>: Take the place of each number and make it into expanded form. EXAMPLE if you have 4928301. For the "4" you would make it 4,000,000. For the "9" you would make it 900,000. See what I mean? And it keeps going like that. For WORD FORM, you just simply type out the number. :)
Hdhdbbdbdbdbdbfbfbfbbdbdbdbdbbdbdhdhdhshususususue
The square on the hypotenuse is skew and impossible to visually validate. There's nothing to sum. It is a simple calculation to note that <span><span><span>32</span>+<span>42</span>=<span>52</span></span><span><span>32</span>+<span>42</span>=<span>52</span></span></span><span>, but its picture doesn't 'say' that the angle between the 3 and 4 sided square must be 90 degrees.
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Answer:
(C) 50π
Step-by-step explanation:
For this problem, we need to find a way to relate the inner circle, to the square, to the outer circle.
Given that we know the area of a circle is πr^2, and our inner circle has a area of 25π, we can find the radius.
25π = πr^2
25 = r^2
5 = r
Note, that the diameter of the inner circle is parallel to the side of the square, meaning that the diameter of the inner circle is the length of the side of the square.
diameter = 2 * radius
d = 2 * 5 = 10.
Now that we know the value of the side of the square, we can find the length of the diagonal of the square, which is the diameter of the outer circle.
Using the properties of the 45-45-90 right triangle, we can say that the diagonal of the square is the length of the side times sqrt(2).
Outer_Diameter = 10 * sqrt(2)
Now to find the outer area, we need the formula for the area of a circle. Note that the diameter is twice the radius, so we will simply divide by 2.
A = πr^2
A = π * [ ( 10 * sqrt(2) ) / 2 ]^2
A = π * [ 5 * sqrt(2) ] ^2
A = π * 25 * 2
A = 50π
So the area of the outer circle is 50π.
Cheers.
