The answer is <span>4 times the 4th root of 5. You would take out a 16, and the fourth root of that is 2 so 2 x 2 = 4 which would be outside the fourth root of 5.
Hope this helps! :)</span>
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Answer:
2
Step-by-step explanation:
The products of chord lengths are the same for the intersecting chords:
AQ×BQ = CQ×DQ
6×12 = CQ×(38 -CQ)
This gives a quadratic in CQ:
CQ² -38CQ +72 = 0 . . . . . write in standard form
(CQ -2)(CQ -36) = 0 . . . . . factor the quadratic
CQ = 2 or 36 . . . . . . . values of CQ that make the factors zero
The minimum length of CQ is 2 units. (DQ will be 36.)
Well you already know a whole circle is 360 and if there are any angles that already have there measurements you can use those and find the percent that isn’t accounted for is your angle......or just use a protractor
2^2(-9 + 4)
First step: solve the brackets.
2^2(-5)
Second step: solve the exponent.
4(-5)
Final step: multiply.
-20
PS: Could you please mark as brainliest? Thanks!
Answer:
-13 ≤ x ≤ 11
Step-by-step explanation:
|x+1| ≤12
There are two solutions, one positive and one negative, remembering to flip the inequality for the negative
x+1 ≤12 x+1 ≥-12
Subtract 1 from each side
x+1-1 ≤12-1 and x+1-1 ≥-12-1
x ≤11 and x ≥-13
-13 ≤ x ≤ 11
