The answer is: 66m + 16 !! hope that helps
The range of the primary phone data is 0.28.
The range of the secondary phone data is 0.73.
The median of the secondary phone data is 0.48 g larger than the median of the primary phone data.
To find the range of the primary phone data, subtract the largest and the smallest values:
0.35 - 0.07 = 0.28
To find the range of the secondary phone data, subtract the largest and the smallest values:
1.18 - 0.45 = 0.73
To find the median of the primary phone data, arrange the data from least to greatest and then find the middle value:
0.07, 0.08, 0.1, 0.1, 0.12, 0.13, 0.14, 0.22, 0.35 - the middle is 0.12
To find the median of the secondary phone data, arrange the data from least to greatest and then find the middle value:
0.45, 0.45, 0.5, 0.6, 0.6, 0.68, 0.82, 0.91, 1.18 - the middle is 0.6
The median of the secondary phone data, 0.6, is 0.6-0.12 larger than the median of the primary phone data; 0.6-0.12 = 0.48
9514 1404 393
Answer:
50 m/s
Step-by-step explanation:
Ian's rate was ...
(180,000 m)/(3600 s) = 50 m/s
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There are 1000 meters in a kilometer, and there are 3600 seconds in 1 hour. To find meters per second, divide meters by seconds.
Answer:
3 and 16
Step-by-step explanation:
The answer is 1/16
Since 2^4 = 16, 2^-4 = 1/16 because of the negative exponent. Let me know if you need me to explain is some more!
