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2 years ago

Help please I really need this !!!!

Mathematics

1 answer:

stealth61 [152]2 years ago

5 0

Answer:

List 2

Step-by-step explanation:

i got it right

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15. Joey indicated that the Bayugan City can be found at coordinates (-1 1/2,0). Do you agree with Joey? Why or why not?

Arturiano [62]

Answer:

The answer is "False".

Step-by-step explanation:

In this question, I disagree with Joey since the town of Bayugan has been at co-ordinates (0, $-1\frac{1}{2}$ ) which would be contradictory to Joey.

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2 years ago

Use the diagram below to solve. The m<1=29x+12 and the m<5=15x-8

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3 years ago

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Anni [7]

Answer:

Step-by-step explanation:

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3 years ago

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If a point is picked at random from the largest rectangle, what is the probability that it is not shaded? Assume that all of the

tia_tia [17]

$|\Omega|=32\\ |A|=14\\\\ P(A)=\dfrac{14}{32}=\dfrac{7}{16}\approx44\%$

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3 years ago

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Electric charge is distributed over the disk x2 + y2 ≤ 16 so that the charge density at (x, y) is rho(x, y) = 2x + 2y + 2x2 + 2y

professor190 [17]

Answer:

Required total charge is $256\pi$ coulombs per square meter.

Step-by-step explanation:

Given electric charge is dristributed over the disk,

$x^2=y^2\leq 16$ so that the charge density at (x,y) is,

$\rho (x,y)=2x+2y+2x^2+2y^2$

To find total charge on the disk let Q be the total charge and $x=r\cos\theta,y=r\sin\theta$ so that,

$Q={\int\int}_Q\rho(x,y) dA$ where A is the surface of disk.

$=\int_{0}^{2\pi}\int_{0}^{4}(2x+2y+2x^2+2y^2)dA$

$=\int_{0}^{2\pi}\int_{0}^{4}(2r\cos\theta+2r\sin\theta+2r^2 \cos^{2}\theta+2r^2\sin^2\theta)rdrd\theta$

$=2\int_{0}^{2\pi}\int_{0}^{4}r^2(\cos\theta+\sin\theta)drd\theta+2\int_{0}^{2\pi}\int_{0}^{4}r^3drd\theta$

$=\frac{2}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)\Big[r^3\Big]_{0}^{4}d\theta+2\int_{0}^{2\pi}\Big[\frac{r^4}{4}\Big]d\theta$

$=\frac{128}{3}\int_{0}^{2\pi}(\sin\theta+\cos\theta)d\theta+128\int_{0}^{2\pi}d\theta$

$=\frac{128}{3}\Big[\sin\theta-\cos\theta\Big]_{0}^{2\pi}+128\times 2\pi$

$=\frac{128}{3}\Big[\sin 2\pi-\cos 2\pi-\sin 0+\cos 0\Big]+256\pi$

$=256\pi$

Hence total charge is $256\pi$ coulombs per square meter.

3 0

3 years ago