Question

Please help:

Answer 1

Answer:

Smaller x value = -1 and y = -2.

Larger x value =  1 and y = 2.

Step-by-Step explanation:

x^2 + y^2 = 5

y = 2x

Substitute y = 2x into the first equation:

x^2 + (2x)^2 = 5

x^2 + 4x^2 = 5

5x^2 = 5

x^2 = 1

x = ±1

So y = 2 *  ±1 =  ±2

Answer 2

Answer:

(- 1, - 2 ) and (1, 2 )

Step-by-step explanation:

Given the 2 equations

x² + y² = 5 → (1)

y = 2x → (2)

Substitute y = 2x into (1)

x² + (2x)² = 5

x² + 4x² = 5

5x² = 5 ( divide both sides by 5 )

x² = 1 ( take the square root of both sides )

x = ± $\sqrt{1}$ = ± 1

Substitute these values into (2) for corresponding values of y

x = - 1 : y = 2(- 1) = - 2 ⇒ (- 1, - 2 )

x = 1 : y = 2(1) = 2 ⇒ (1, 2 )

The solution with smaller x- value is (- 1, - 2 )

The solution with the larger x value is (1, 2 )