The intersection point of the two lines is (2,1,0).
The respective direction vectors are
L1: <1,2,4>
L2: <4,1,15>
Since the normal vector of the required plane is perpendicular to both direction vectors, the normal vector of the plane is obtained by the cross product of L1 and L2.
i j k
1 2 4
4 1 15
=<30-4, 16-15, 1-8>
=<26, 1, -7>
We know that the plane must pass through (2,1,0), the equation of the plane is
26(x-2)+1(y-1)-7(z-0)=0
simplifying,
26x+y-7z=52+1+0=53
or
26x+y-7z=53
Check:
Put points on L1 in the plane
26(t+2)+(2t+1)-7(4t+0)=53 ok
For L2,
26(4t+2)+(t+1)-7(15t+0)=53 ok
Answer:
The correct option is C.
Step-by-step explanation:
Consider the provided information.
Four conditions of a binomial experiment:
There should be fixed number of trials
Each trial is independent with respect to the others
The maximum possible outcomes are two
The probability of each outcome remains constant.
Now, observe the provided options:
Option A and B are not possible as they doesn't satisfy the conditions of binomial experiment which is there must be fixed number of trials.
Now observe the option C which state that there must be fixed number of trials, it satisfy the condition of a binomial experiment.
Therefore, the correct option is C.
Answer:
√72
Decimal Form:
1.32287565…
Step-by-step explanation:
To subtract fractions, find the LCD and then combine.
