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2 years ago

To find the result when

Mathematics

1 answer:

Liula [17]2 years ago

5 0

Answer:

answer is 51 hope i'm corret

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What is the range? 6 7 8 7 10

jeka94

Range= 4

Range is the highest number minus the lowest number, 10-6=4

4 0

3 years ago

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The perimeter of this rectangle is 24cm. If the length is 8 cm, what is the height?

Gemiola [76]

Answer:

Step-by-step explanation:

P = s+s+s+s

length = 8

8x2=16

24-16=8

8 / 2 = 4

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3 years ago

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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).

ddd [48]

Answer:

$f'(x) = 4x^2 - 3$ for $x \le -3$

Step-by-step explanation:

See attachment for proper question

Given

$f(x) = -\frac{1}{2}\sqrt{x + 3}$

For

$x \ge -3$

Required

Determine the inverse function

$f(x) = -\frac{1}{2}\sqrt{x + 3}$

Replace f(x) with y

$y = -\frac{1}{2}\sqrt{x + 3}$

Swap the positions of x and y

$x = -\frac{1}{2}\sqrt{y + 3}$

Multiply both sides by -2

$-2 * x =-2 * -\frac{1}{2}\sqrt{y + 3}$

$-2x =\sqrt{y + 3}$

Square both sides

$(-2x)^2 =(\sqrt{y + 3})^2$

$4x^2 =y + 3$

Make y the subject

$y = 4x^2 - 3$

The inverse has been solved. So, we need to replace y with f'(x)

$f'(x) = 4x^2 - 3$

Next, is to determine the interval

$x \ge -3$

Change inequality to $\le$

$x \le -3$

Hence, the inverse function is:

$f'(x) = 4x^2 - 3$ for $x \le -3$

7 0

3 years ago

Hello someone please help. 20 brainly poins

marusya05 [52]

Answer:

I think either A or B. not sure though

Step-by-step explanation:

4 0

2 years ago

6300/90???? PLS helpppp

dmitriy555 [2]

Answer: 70

Step-by-step explanation: 6300/90=70 Brainliest please?

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3 years ago