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3 years ago

Who had this before if so can I get help

Mathematics

1 answer:

telo118 [61]3 years ago

6 0

2*3+4=10

5+2x2=9

4-3+2=3

4*3+2=14

20-4x3+6=14

16-30/2+11=12

24/6*5=20

15/5+2=5

2+2*9-5=15

12-3+4*2=1

12/3+3*4=16

9-6/3=7

16-3*4=4

36/4/9=1

The last one is yours

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alexdok [17]

Answer:

$H_{0}: \mu \leq 600\text{ dollars}\\H_A: \mu > 600\text{ dollars}$

Step-by-step explanation:

We are given the following in the question:

Manager's claim: The mean guest bill for a weekend is $600 or less.

A member of the hotel’s accounting staff noticed that the total charges for guest bills have been increasing in recent months.

A sample of weekend guest bills were collected to test the manager’s claim.

We design the null and alternate hypothesis in the following manner:

$H_{0}: \mu \leq 600\text{ dollars}\\H_A: \mu > 600\text{ dollars}$

Conclusion when null hypothesis cannot be rejected:

When we fail to reject the null hypothesis and accept the null hypothesis, thus, we have enough evidence to support the manager's claim that the mean guest bill for a weekend is $600 or less.

Conclusion when null hypothesis can be rejected:

When the null hypothesis is rejected, we accept the alternate hypothesis.

Thus, there are not sufficient evidence to support the manager's claim that the mean guest bill for a weekend is $600 or less.

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Masteriza [31]

We have been given the expression

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In order to write the given expression in this form, we can use some exponent property.

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On using the property (1), we have

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