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Elan Coil [88]
3 years ago
15

For the equation, complete the solution. 7x + y = −18

Mathematics
2 answers:
Alex777 [14]3 years ago
8 0

Answer:

x= - 18/7 - 1/7y, y

or if you are solving for y= -18-7x, x

( SEE OTHER IMAGE)

Step-by-step explanation:

See image below:)

Sphinxa [80]3 years ago
6 0

Answer:

x= \frac{- 18 - y }{7}

y = - 18 - 7x

Step-by-step explanation:

7x + y = - 18

7x + y - y = - 18 - y

7x = - 18 - y

\frac{7x}{7}= \frac{- 18 - y }{7}

x= \frac{- 18 - y }{7}

7x + y = - 18

7x - 7x + y = - 18 - 7x

y = - 18 - 7x

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Please help! Correct answer only!
gulaghasi [49]

Answer:

<em>Probability ≈ 0.1071</em>

Step-by-step explanation:

Consider steps below;

Total Possible Outcomes - 8C5,\\\\8! / 5! ( 8 - 5 )!,\\1 * 2 * 3 * 4 * 5 * 6 * 7 * 8 / ( 1 * 2 * 3 * 4 * 5 )( 1 * 2 * 3 ),\\\\6 * 7 * 8 / 6 = Combinations - 56,\\\\

Number Of Outcomes - 6C5,\\\\6! / 5! ( 6 - 5 )!,\\1 * 2 * 3 * 4 * 5 * 6 / ( 1 * 2 * 3 * 4 * 5 ) ( 1 ),\\720 / 120 * 1,\\\\Outcomes - 6

Conclusion ; Solution - 6 / 56 = ( About ) 0.1071\\Hope That Helps!

<em>Solution; Probability ≈ 0.1071</em>

5 0
3 years ago
Then p=3.<br> Use the equation k = 3n to find the value of k when n = 3.
Bad White [126]

Answer:

k = 9

Step-by-step explanation:

n = 3, so substitute 3 for n in the equation

k = 3(3)

k = 9

6 0
3 years ago
Two types of defects are observed in the production of integrated circuit boards. It is estimated that 6% of the boards have sol
aalyn [17]

Answer:

(a) 0.09

(b) 0.06

(c) 0.0018

(d) 0.9118

(e) 0.03

Step-by-step explanation:

Let <em>A</em> = boards have solder defects and <em>B</em> = boards have surface defects.

The proportion of boards having solder defects is, P (A) = 0.06.

The proportion of boards having surface-finish defects is, P (B) = 0.03.

It is provided that the events A and B are independent, i.e.

P(A\cap B)=P(A)\times P(B)

(a)

Compute the probability that either a solder defect or a surface-finish defect or both are found as follows:

= P (A or B) + P (A and B)

=P(A)+P(B)-P(A\cap B)+P(A\cap B)\\=P(A)+P(B)\\=0.06+0.03\\=0.09

Thus, the probability that either a solder defect or a surface-finish defect or both are found is 0.09.

(b)

The probability that a solder defect is found is 0.06.

(c)

The probability that both defect are found is:

P(A\cap B)=P(A)\times P(B)\\=0.06\times0.03\\=0.0018

Thus, the probability that both defect are found is 0.0018.

(d)

The probability that none of the defect is found is:

P(A^{c}\cup B^{c})=1-P(A\cup B)\\=1-P(A)-P(B)+P(A\cap B)\\=1-P(A)-P(B)+[P(A)\times P(B)]\\=1-0.06-0.03+(0.06\times0.03)\\=0.9118

Thus, the probability that none of the defect is found is 0.9118.

(e)

The probability that the defect found is a surface finish is 0.03.

6 0
3 years ago
PLZ HELP ME!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!:(
-Dominant- [34]

Sorry for taking so long, it wont let me type a while ago. I have it all fix now hehe. I took a picture of my work, ask me if you still don’t understand.

8 0
3 years ago
Solve this equation <br><br> 1 . B/-7 = 4
weqwewe [10]

Step-by-step explanation:

B/-7 = 4

Cross multiple

-7×4 = B

-28 = B

8 0
3 years ago
Read 2 more answers
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