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Stels [109]
2 years ago
5

Determine f(a+h)-f(a)/h for f(x)=x^2+5x

Mathematics
1 answer:
Crank2 years ago
4 0

Answer:

2x + 5

ok.. slightly silly question...

you will eventually learn that this formula is the

formula for the "derivative" in calculus....

Ax^{b} becomes (a*b)  x^{b-1}

2x + 5

Step-by-step explanation:

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Is -90 + (-5) positive or negative? Explain how you know.
horrorfan [7]

Answer:

negative because since -90 and -5 are both negative just add and keep it the sign which is -95

hope this helps

have a good day :)

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Describe how you would convince a friend that sin(x + y) does not equal sin x + sin y.
Citrus2011 [14]

Answer:

Step-by-step explanation:

PEMDAS

anything done in the parentheses comes first

so you have to add first then multiply

this is not the distributive property unless the two numbers in parentheses are not like terms

4 0
2 years ago
Which is the sum of -4 and its additive inverse?
Aneli [31]

Answer:

-4 +4 =0

Step-by-step explanation:

The sum of a number and its' additive inverse is 0

The additive inverse of -4 is 4

-4 +4 =0

3 0
2 years ago
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How do we write the difference of a number and 4?
rjkz [21]

Answer:

x-4

Step-by-step explanation:

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8 0
3 years ago
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Simplify by expressing fractional exponents instead of radicals
igomit [66]

Answer:

a^{\frac{1}{2}}b^{\frac{1}{2}}

Step-by-step explanation:

Given:

The expression in radical form is given as:

\sqrt{ab}

We need to express this in fractional exponent form.

We know that,

\sqrt a=a^{\frac{1}{2}}

Also, \sqrt{ab}=\sqrt a\times \sqrt b

Now, clubbing both the properties of square root function, we can rewrite the given expression as:

\sqrt{ab}=\sqrt a \times \sqrt b\\\\\sqrt{ab}=a^{\frac{1}{2}}\times b^{\frac{1}{2}}\\\\\therefore \sqrt{ab}=a^{\frac{1}{2}}b^{\frac{1}{2}}

So, the given expression in fractional exponents form is a^{\frac{1}{2}}b^{\frac{1}{2}}.

3 0
3 years ago
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