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creativ13 [48]
3 years ago
15

Finding side lengths with trigonometry

Mathematics
1 answer:
Hatshy [7]3 years ago
7 0

Answer:

42.1

Step-by-step explanation:

tan 39 = 52 / x

x = 52 tan39

x = 42.1

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Andreyy89
To find the relative frequency, divide the frequency by the total number of data values. To find the cumulative relative frequency, add all of the previous relative frequencies to the relative frequency for the current row.
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3 years ago
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Patel made a deposit into an account that earns 5%simple interest. After 10 years Patel had earned $1500 in interest. How much w
Delicious77 [7]
\bf ~~~~~~ \textit{Simple Interest Earned}\\\\
I = Prt\qquad 
\begin{cases}
I=\textit{interest earned}\to &\$1500\\
P=\textit{original amount deposited}\\
r=rate\to 5\%\to \frac{5}{100}\to &0.05\\
t=years\to &10
\end{cases}
\\\\\\
1500=P(0.05)(10)\implies \cfrac{1500}{(0.05)(10)}=P
7 0
3 years ago
What is the value of x if e^3x+6 = 8?
topjm [15]

We can write any number n in the form e^{\ln(n)}, since e^x and \ln(x) are inverse functions, so that

e^{3x+6} = 8 \iff e^{3x+6} = e^{\ln(8)}

The bases are the same on both sides, so the exponents must be equal.

3x + 6 = \ln(8)

Solve for x :

3x = \ln(8) - 6

x = \boxed{\dfrac{\ln(8) - 6}3}

5 0
3 years ago
What is the answer for this Problem?
geniusboy [140]

Answer:

Increasing on the interval(s) -2\leq x\leq -4

Decreasing on the interval(s) -1\leq y\leq 1

Step-by-step explanation:

Anytime the graph is going upward, the function is increasing. However, anytime the graph goes down, the function is decreasing. Look at the image below for further reference. Also, when the function is increasing, the slope is positive, and when the function is decreasing the slope is negative.

The increasing interval of the graph is -3

The decreasing interval of the graph is 0.5

Since the values are in the middle of the interval, it automatically becomes the answer.

5 0
3 years ago
Tim and Tom are painters. Tim and Tom are painting a crate. Tom paints 10 sq ft per minute. They painted a particular crate in 1
slava [35]
Tom-------------- >10 sq ft per minute

Tim------------------- >3.5*10=35 sq ft per minute

 Both painters (10+35)=45 sq ft per minute

 let's assume a cubic unit crate----------> V1=1*1*1=1 feet3

<span>the total surface of the cube is S1=6*(1*1)=6 </span>sq ft

 if the volume of the cube increases twice 

V2=2 feet3 ------------------- >    2=x*x*x------------- >x=2^(1/3)

And the S2=6*(2^(1/3)*<span> 2</span>^(1/3)=9.5244 sq ft

V2/V1=9.5244/6=1.5874

Therefore

If Tim and Tom----------------------- > take 1 day----------- > to paint a crate V1

For the crate V2------------- > take 1.5874 days 

assuming an 8-hour work day

 0.5874*8=4.70 hr-------------- > 4 h 42 min

 The answer is 1 day 4h 42 min

6 0
4 years ago
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