3 years ago

Help me please on hegarty maths

Mathematics

1 answer:

Orlov [11]3 years ago

6 0

Answer:

29.5cm^2

Step-by-step explanation:

3 × 4 = 12

4 × 2.5 = 10

3 × 2.5 = 7.5

12+10+7.5=29.5

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Find the unknow side of the right triangle 2. b=73.6 cm b= 19.0

shusha [124]

Assumed 73.6cm is the hypotenuse.

$a^{2} + b^{2} = c^{2}$
$19^{2} + b^{2} = 73.6^{2}$
$b^{2}$ = $73.6^{2} -19^{2}$
$b^{2}$ = $5055.96$
$b$ = $71.1$

Assumed 73.6cm is not the hypotenuse.
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3 years ago

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3 years ago

prove that the equation (a^(2)-5ab)-(7-3ab)+(2ab-a^(2)) is equivilent to -7 please show it step by step! Tysm!

dem82 [27]

Answer:

Step-by-step explanation:

(a^2 - 5ab) - (7 - 3ab) + (2ab - a^2) = -7

a^2 - 5ab -7 +3ab + 2ab -a^2 = -7 [combine like terms]

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3 years ago

Read 2 more answers

A surveyor wishes to determine the height of a mountain. At a given position he measures the angle of elevation to the top as 43

Usimov [2.4K]

Answer:

4,486.93 ft

Step-by-step explanation:

Let 'h' be the height of the mountain and 'x' be the horizontal distance between the first position measured and the top of the mountain.

Two right triangles can be modeled such that their tangent relationships yield:

$tan(43.66) = \frac{h}{x}\\tan(38.2) = \frac{h}{x+1000}$

Solving the linear system:

$x= \frac{h}{tan(43.66)}\\x = \frac{h}{tan(38.2)} -1000\\\frac{h}{tan(43.66)}=\frac{h}{tan(38.2)} -1000\\1000 = 0.222869*h\\h=4,486.93\ ft$

The mountain is 4,486.93 ft high.

7 0

3 years ago