I THINK YOU FORGOT TO POST THE COMPLETE Q.
The volume of a cube is V=s^3, so s=V^(1/3).
The area of a cube is A=6s^2, using s found above we have:
A=6(V^(2/3))
Let V and S be the volume and area of the larger and v and s be the volume and area of the smaller cube.
A:a
6(V^(2/3)):6(v^(2/3))
V^(2/3):v^(2/3), we are given that V=216 and v=64 so
216^(2/3):64^(2/3)
36:16
9:4
It's already reduced it remains as 69/80 because the is no greater common factor between the two.
Answer:
It's 4 ;)
Step-by-step explanation:
Real numbers that are opposite would be a way that they would cancel out, leaving the imaginary number components.
