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tankabanditka [31]
2 years ago
8

The price of a pair of jeans was reduced from $20 to $15. By what

Mathematics
1 answer:
inna [77]2 years ago
8 0
Answer: 25%

Explanation:
1. Turn it into a fraction (15/20)
2. Divide the numerator (15) by the denominator (20). (15÷20=0.75)
3. Subtract 0.75 from 1 (1-0.75=0.25)
4. Turn 0.25 into a percentage by taking away the “0.” and adding a “%” at the end (25%)
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Factor completely 4xy − 7x 20y − 35. (x 5)(4y − 7) (x − 5)(4y 7) (x − 5)(4y − 7) (x 5)(4y 7).
yuradex [85]

Answer:

A)

Step-by-step explanation:

Given expression:

To factor the given expression completely.

Solution:

In order to factor the expression, we will factor in pairs.

We will factor the G.C.F of the terms in the pairs.

G.C.F. of  and  can be given as:

Thus, G.C.F. =

G.C.F. of  and  can be given as:

Thus, G.C.F. =

The expression after factoring the G.C.F. pairs is given as:

Taking G.C.F. of the whole expression as  is a common term.

The expression is completely factored.

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Which of the following points are more than 5 units from the point P(−2, −2)? Select all that apply. A A (2, 1) B B (4, −1) C C
netineya [11]

The distance between any 2 points P(a,b) and Q(c,d) in the coordinate plane, is given by the formula:<span>

<span> |PQ|= \sqrt{ (a-c)^{2} + (b-d)^{2}}</span></span>


Using this formula we calculate the distances |PA|, |PB|, |PC|, |PD| and |PE| and compare to 5.


|PA|= \sqrt{ (-2-2)^{2} + (-2-1)^{2}}= \sqrt{16+9}= \sqrt{25}=5

|PB|= \sqrt{ (-2-4)^{2} + (-2+1)^{2}}= \sqrt{36+1}= \sqrt{37} \approx 6

|PC|= \sqrt{ (-2-2)^{2} + (-2+3)^{2}}= \sqrt{16+1}= \sqrt{17}\approx4

|PD|= \sqrt{ (-2+6)^{2} + (-2+6)^{2}}= \sqrt{16+16}= \sqrt{32}\ \textgreater \  \sqrt{25}=5

|PE|= \sqrt{ (-2+5)^{2} + (-2-1)^{2}}= \sqrt{9+9}= \sqrt{16}=4


Answer: B and D





3 0
3 years ago
If sum of first 6 digits of AP is 36 and that of the first 16 terms is 255,then find the sum of first ten terms.
Cloud [144]

Answer:

100

Step-by-step explanation:

We have the sum of first n terms of an AP,

Sn = n/2 [2a+(n−1)d]

Given,

36= 6/2 [2a+(6−1)d]

12=2a+5d ---------(1)

256= 16/2 [2a+(16−1)d]

32=2a+15d ---------(2)

Subtracting, (1) from (2)

32−12=2a+15d−(2a+5d)

20=10d ⟹d=2

Substituting for d in (1),

12=2a+5(2)=2(a+5)

6=a+5 ⟹a=1

∴ The sum of first 10 terms of an AP,

S10 = 10/2 [2(1)+(10−1)2]

S10 =5[2+18]

S10 =100

This is the sum of the first 10 terms.

Hope it will help.

4 0
3 years ago
Read 2 more answers
Solve for Y<br> Answers choices <br> Y=120<br> Y=60<br> Y=20<br> Y=10
fomenos

Answer:I’m going with 60 but I might be wrong cuz I did this in my head and I am not good with mental math so

Step-by-step explanation:

3 0
2 years ago
How many whole groups of 2 can we make with 7?
nataly862011 [7]

Answer:

We can make 3 whole groups of 2.

Hope that helps. x

Step-by-step explanation:

2, 4, 6, 8

The closest number near to 7 is 6 so we do 6 divided by 2 which equals 3.

6 0
2 years ago
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