Our line equation is
where the slope m=1/2 and the y-intercept b is b=7.
Parallel lines has the same slope. Hence, their slope is always
in this case.
What question Would that be
If you want the answer in point slope form then,
y-y1 = m(x-x1)
y-c = m(x-a)
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If you want the answer in slope intercept form, then solve for y
y-c = m(x-a)
y-c = mx-ma
y-c+c = mx-ma+c
y = mx-ma+c
y = mx+c-ma
y = mx+(c-ma)
For this answer in slope intercept form the slope is m and the y intercept is c-ma
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If you want the answer in standard form, then get the variable terms to the left side. Have the constant terms on the right side.
y = mx+c-ma
y-mx = mx+c-ma-mx
-mx+y = c-ma
Optionally you can multiply both sides by -1 to get mx-y = -c+ma but it will depend on your book if this step is carried out or not.
The first step can be subtracting 2x from both sides leaving the equation with 6x + 3 = -15
Answer:
y = 4
Step-by-step explanation:
The graph passes through the point (3, 4), which means that the value of the function is 4 when x=3.
