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d1i1m1o1n [39]
3 years ago
9

Help me on my geometry test

Mathematics
2 answers:
Crazy boy [7]3 years ago
7 0

Answer: 7.5

Step-by-step explanation:

Rudik [331]3 years ago
4 0
It’s F. hahahahahahahaha
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Factor completely n^4-1
taurus [48]
N^4 - 1 = (n^2 - 1)(n^2 + 1)

            =     (n + 1)(n - 1)(n^2 + 1)
4 0
3 years ago
Read 2 more answers
What two rational expressions sum to 2x+3/x^2-5x+4
Anni [7]

Answer:

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}

Step-by-step explanation:

Given the rational expression: \frac{2x + 3}{x^2 - 5x + 4}, to express this in simplified form, we would need to apply the concept of partial fraction.

Step 1: factorise the denominator

x^2 - 5x + 4

x^2 - 4x - x + 4

(x^2 - 4x) - (x + 4)

x(x - 4) - 1(x - 4)

(x- 1)(x - 4)

Thus, we now have: \frac{2x + 3}{(x- 1)(x - 4)}

Step 2: Apply the concept of Partial Fraction

Let,

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}

Multiply both sides by (x - 1)(x - 4)

\frac{2x + 3}{(x- 1)(x - 4)} * (x - 1)(x - 4) = (\frac{A}{x- 1} + \frac{B}{x - 4}) * (x - 1)(x - 4)

2x + 3 = A(x - 4) + B(x - 1)

Step 3:

Substituting x = 4 in 2x + 3 = A(x - 4) + B(x - 1)

2(4) + 3 = A(4 - 4) + B(4 - 1)

8 + 3 = A(0) + B(3)

11 = 3B

\frac{11}{3} = B

B = \frac{11}{3}

Substituting x = 1 in 2x + 3 = A(x - 4) + B(x - 1)

2(1) + 3 = A(1 - 4) + B(1 - 1)

2 + 3 = A(-3) + B(0)

5 = -3A

\frac{5}{-3} = \frac{-3A}{-3}

A = -\frac{5}{3}

Step 4: Plug in the values of A and B into the original equation in step 2

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{A}{x- 1} + \frac{B}{x - 4}

\frac{2x + 3}{(x- 1)(x - 4)} = \frac{-5}{3(x- 1)} + \frac{11}{3(x - 4)}

7 0
3 years ago
I Need Help With These
Dmitrij [34]
Notice below the picture

the one on the left-hand-side, is the 30-60-90 rule

those are the ratios, for 16), the hypotenuse (slanted side), is 4

for the ratios, that means that 4 = 2x, if you solve that for "x", that simply means "x" is 2

now, just use that value you found for "x" from the hypotenuse ratio, and use it to get the other two sides

what's the perimeter? all three sides added together

for 17)     \bf \textit{area of an equilateral triangle}\\\\
A=\cfrac{s^2\sqrt{3}}{4}\qquad s=\textit{length of one side}

4 0
4 years ago
A student translated the phrase below into an algebraic expression, and then evaluated it for g = one-fourth. Is the student's w
iragen [17]

Answer:

The correct evaluation is 1 1/3 (one and one-third) and not 16 and one-third

Step-by-step explanation:

The student was wrong in his evaluation because the correct result should be 1 1/3 (one and one-third) and not 16 and one-third

The expression '1/3 more than the product of four and a number' means

(4g + 1/3)

Evaluating the expression when g = 1/4

You will have

4×1/4 + 1/3

= 1/1 + 1/3

Find the LCM of 1 and 3 and add

= (3+1)/3

=4/3

= 1 1/3

The correct evaluation is 1 1/3 (one and one-third) and not 16 and one-third

6 0
3 years ago
Read 2 more answers
Multiply (2n + 2)(2n – 2) A. 4n 2 – 4 B. 4n 2 – 4n – 4 C. 4n 2 + 2n – 4 D. 4n 2 + 4n – 4
sattari [20]
This system can be a bit tricky unless you write it out:
(2n + 2)(2n - 2) ~ First you have to take one variable and multiply it to each of the other two variables, like:
2n * 2n ~ And:
2n * -2 ~ This gives you:
4n^2 - 4n
Now we do this with the other:
2 * 2n
2 * -2
4n - 4
Now we combine them both while adding like terms:
4n^2 - 4
Therefore your answer is: A. 4n^2 - 4
(This is due to how when having the positive 4n subtracted by the negative it cancels it out. Leaving us with the remaining two terms left.)

I hope this helps, have a great rest of your day! ^ ^
~Ghostgate
7 0
3 years ago
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