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Aliun [14]
2 years ago
12

In angle abcd if b=50 find the other angles ​

Mathematics
2 answers:
klemol [59]2 years ago
6 0

Answer:

can u show the angels?

Step-by-step explanation:

Tom [10]2 years ago
4 0

Answer:

angel abcd is not possible

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Danielle worked three days last week for a total of 18.25 hours. She worked 6.5 hours on Monday and 5.75 hours on Wednesday. How
svet-max [94.6K]

Answer:

She worked for 6 hours on Saturday.

Step-by-step explanation:

Number of hours worked by Danielle last week = 18.25 hours

She worked for three days, Monday, Wednesday and Saturday.

Let she worked on Saturday = x hours

Therefore, total hours worked by Danielle in three days = 6.5 + 5.75 + x

And the equation will be,

6.5 + 5.75 + x = 18.25

12.25 + x = 18.25

x = 18.25 - 12.25

x = 6

Therefore, she worked for 6 hours on Saturday.

7 0
3 years ago
100 m
iren [92.7K]

B. 60 m is the height of the triangle

3 0
2 years ago
a store is having a sale on chocolate chips and walnuts. for 3 pounds of chocolate chips and 5 pounds of walnuts the total cost
Delvig [45]
If you set you the equations such as 3c+5w=23 and 6c+2w=20 and then solve the first equation for c, you get c= (23-5w)/3 Taking that equation and substituting it for 'c' in the second equation (so the second equation becomes: 6((23-5w)/3)+2w=20  ) you get w=3.25 If you plug that back into your first equation (so it now becomes: 3c+5(3.25)=23 ) you get c=2.25 So the answer would be walnuts cost $3.25 per lb and choc. chips cost $2.25 per lb. 
6 0
3 years ago
5.1million x 2.9 thousand
d1i1m1o1n [39]

Answer:

fourteen billion seven hundred ninety millio

4 0
3 years ago
The circle given by : x^2 + y^2 - 6y - 12 = 0 can be written as:
deff fn [24]

Step-by-step explanation:

Given equation of circle is,

{x}^{2}  +  {y}^{2}  - 6y - 12 = 0 \\ by \: compairing \: it \: with \:   \\ {x}^{2}  +  {y}^{2}   + 2gx + 2fy = 0 \: we \: get \\2 g = 0 \: or \: g = 0 \\ 2f=  - 6 \\ or \: f=  - 3 \\ c =  - 12

again the another form of circle is,

{x}^{2}  +  {(y - k)}^{2}  = 21 \\ or \:  {x}^{2}  + {y}^{2}  - 2ky +  {k}^{2}  - 21 = 0 \\ by \: compairing \:it \: with \:  \\ {x}^{2}  +  {y}^{2}   + 2gx + 2fy = 0 \: we \: get  \\ g = 0 \\f =  - k \\ c =  {k}^{2}  - 21

now equating the values of f in both equations,

-k=-3

i.e. k=3

therefore k=3

4 0
3 years ago
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