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Aleonysh [2.5K]
2 years ago
8

Solve for m k=mvsquared/2​

Mathematics
1 answer:
Lerok [7]2 years ago
4 0

Answer:

m=\frac{2k}{v^{2} }

Step-by-step explanation:

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Michelle needs to buy some wood to build a rectangular box that is 12 inches long 8 inches wide and 10 inches high and net worth
Anettt [7]
Since it’s asking for square inches on a rectangular prism, this is solving for surface area. So we use the following formula:
2(h*w)+2(h*l)+2(w*l)=A

2(10*8)+2(10*12)+2(8*12)
2(80)+2(120)+2(96)
160+240+192
592

592 sq. in.
3 0
2 years ago
The U.S. and many other countries have recently tightened airport security. A sociologist is interested in estimating the propor
melisa1 [442]

Answer:

0.0073 < 0.05, which means that we reject the null hypothesis and conclude that the true proportion of interest is higher than 0.7.

Step-by-step explanation:

Conduct a test to determine whether the true proportion of interest is higher than 0.7.

This means that the null hypothesis is: H_{0}: p = 0.7

And the alternate hypothesis is: H_{a}: p > 0.7

The test statistic is:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the value tested at the null hypothesis, \sigma is the standard deviation and n is the size of the sample.

0.7 is tested at the null hypothesis:

This means that \mu = 0.7, \sigma = \sqrt{0.7*0.3}

The sociologist found that 375 of the 500 travelers randomly selected and interviewed indicated that the airports were safe.

This means that n = 500, X = \frac{375}{500} = 0.75

Value of the z-statistic:

z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

z = \frac{0.75 - 0.7}{\frac{\sqrt{0.7*0.3}}{\sqrt{350}}}

z = 2.44

P-value of the test:

Probability of z being larger than 2.44, that is, a proportion larger than 0.75.

This is, looking at the z-table, 1 subtracted by the pvalue of Z = 2.44. S

Z = 2.44 has a pvalue of 0.9927

1 - 0.9927 = 0.0073

0.0073 < 0.05, which means that we reject the null hypothesis and conclude that the true proportion of interest is higher than 0.7.

8 0
3 years ago
PLEASE HELP WITH GRAPH LAST QUESTION I NEED ​
SVETLANKA909090 [29]

Answer:

\sf g(x) = -1(x+3)^2 -2

Explanation:

\sf original \ graph:  \ y=-x^{2}

the graph is translated 3 units to the left and 2 units down.

vertex: (-3,-2) point: (-1,-6)

\sf so \ new \ graph :

\sf y = a(x-h)^2 +k

\sf -6 = a(-1-(-3))^2 -2

\sf -6 = 4a -2

\sf 4a = -4

\sf a = -1

\sf equation:

\sf y = a(x-h)^2 +k

\sf y = -1(x+3)^2 -2

6 0
2 years ago
Read 2 more answers
Prove or disprove that the point (√5, 12) is on the circle centered at the origin and containing the point (-13, 0). Show your w
pav-90 [236]

Using the equation of the circle, it is found that since it reaches an identity, the point (√5, 12) is on the circle.

<h3>What is the equation of a circle?</h3>

The equation of a circle of center (x_0, y_0) and radius r is given by:

(x - x_0)^2 + (y - y_0)^2 = r^2

In this problem, the circle is centered at the origin, hence (x_0, y_0) = (0,0).

The circle contains the point (-13,0), hence the radius is found as follows:

x^2 + y^2 = r^2

(-13)^2 + 0^2 = t^2

r^2 = 169

Hence the equation is:

x^2 + y^2 = 169

Then, we test if point (√5, 12) is on the circle:

x^2 + y^2 = 169

(\sqrt{5})^2 + 12^2 = 169

25 + 144 = 169

Which is an identity, hence point (√5, 12) is on the circle.

More can be learned about the equation of a circle at brainly.com/question/24307696

#SPJ1

6 0
2 years ago
Name a segment skew to PX
sergiy2304 [10]

Answer:

I,

Step-by-step explanation:

5 0
2 years ago
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