(1073 + 1108 + x) / 3 = 1000
(2181 + x) / 3 = 1000 ....multiply both sides by 3
2181 + x = 1000 * 3
2181 + x = 3000
x = 3000 - 2181
x = 819 <== they would need to earn $ 819 on Sunday
The standard form for the equation of a circle is :
<span><span><span> (x−h)^</span>2</span>+<span><span>(y−k)^</span>2</span>=<span>r2</span></span><span> ----------- EQ(1)
</span><span> where </span><span>handk</span><span> are the </span><span>x and y</span><span> coordinates of the center of the circle and </span>r<span> is the radius.
</span> The center of the circle is the midpoint of the diameter.
So the midpoint of the diameter with endpoints at (−10,1)and(−8,5) is :
((−10+(−8))/2,(1+5)/2)=(−9,3)
So the point (−9,3) is the center of the circle.
Now, use the distance formula to find the radius of the circle:
r^2=(−10−(−9))^2+(1−3)^2=1+4=5
⇒r=√5
Subtituting h=−9, k=3 and r=√5 into EQ(1) gives :
(x+9)^2+(y−3)^2=5
$7881.18
Step-by-step explanation:
Let the initial Investment be 
. The Interest is compounded on a monthly basis at 12% annual interest rate. After 17 years, the Investment amounts to $60,000.
As the annual interest rate is 12%, the monthly interest rate is 1%.
Since this is a compound interest problem, the total amount can be modeled as follows: 
Here 
is the interest rate, i.e 
, and t is the number of time periods, i.e 
= 
∴ Initial Investment = $7881.18
Answer:
x = 45 when y = 20 and z = 6
Step-by-step explanation:
The general formula here is y = kx/z²
If x = 24 and y = 6, z = 8, so:
y = kx/z² becomes 6 = k(24)/8², and:
6 1
k = ---------------- = -------------- = 16
24/64 4/64
Then y = 16x/z², and so, if y = 20 and z = 6 (check this!), then:
20 = 16x/36, or 16x = 720, or x = 45
x = 45 when y = 20 and z = 6
