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horrorfan [7]
3 years ago
7

Find the center and radius of this circle x^2+y^2-6x-10y+30=0

Mathematics
1 answer:
Vsevolod [243]3 years ago
5 0

Answer:

The circle's centre is at the position (3, 5), and it has a radius of 2

Step-by-step explanation:

First let's put it in a useful format by completing the squares:

x² + y² - 6x - 10y + 30 = 0

x² - 6x + y² - 10y = -30

x² - 6x + 9 + y² - 10y + 25 = -30 + 9 + 25

(x - 3)² + (y - 5)² = 4

This tells us that the centre position is (3, 5) and the radius is √4, or 2

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the company sells the product for 85 cents, so if they sell "x" items, their total revenue or income will be 0.85x.

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as you already know, the break-even point is when.... well, you break even, no losses but no gains either, how much you take in is the same amount that you shelled out, namely R(x) = C(x).

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Hello there!

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