Answer:
The circle's centre is at the position (3, 5), and it has a radius of 2
Step-by-step explanation:
First let's put it in a useful format by completing the squares:
x² + y² - 6x - 10y + 30 = 0
x² - 6x + y² - 10y = -30
x² - 6x + 9 + y² - 10y + 25 = -30 + 9 + 25
(x - 3)² + (y - 5)² = 4
This tells us that the centre position is (3, 5) and the radius is √4, or 2
