9/4y-2=25
9/4y-2+2=27+2
9/4y=27
9/4y*4y=27*4y
9=4y*27,
1/3=4y, (9/27 simpltfies to 1/3, 1/3 divided by 4: 1/3*1/4=1/12)
1/12=y
Answer:y=1/12
Answer:
Solution given:
<u>B: 9x - 4/x^2 - 4</u>
Step-by-step explanation:
.k
Answer:
10,471.2042
Step-by-step explanation:
Tbh Im not too sure
11.4 should be the answer
if you mean tens then it is 10
Answer:
case 2 with two workers is the optimal decision.
Step-by-step explanation:
Case 1—One worker:A= 3/hour Poisson, ¡x =5/hour exponential The average number of machines in the system isL = - 3. = 4 = lJr machines' ix-A 5 - 3 2 2Downtime cost is $25 X 1.5 = $37.50 per hour; repair cost is $4.00 per hour; and total cost per hour for 1worker is $37.50 + $4.00
= $41.50.Downtime (1.5 X $25) = $37.50 Labor (1 worker X $4) = 4.00
$41.50
Case 2—Two workers: K = 3, pl= 7L= r= = 0.75 machine1 p. -A 7 - 3Downtime (0.75 X $25) = S J 8.75Labor (2 workers X S4.00) = 8.00S26.75Case III—Three workers:A= 3, p= 8L= ——r = 5- ^= § = 0.60 machinepi -A 8 - 3 5Downtime (0.60 X $25) = $15.00 Labor (3 workers X $4) = 12.00 $27.00
Comparing the costs for one, two, three workers, we see that case 2 with two workers is the optimal decision.
