Estimate the circumference of the circle to the nearest hundredth. Use π = 3.14

A girl has a square pool with an area of 81 square feet and she adds a patio which is 3 feet wide around the pool what is the to

Scorpion4ik [409]

Answer:

$\text{Total area of the pool and patio combined}=225\text{ ft}^2$

Step-by-step explanation:

We have been given that A girl has a square pool with an area of 81 square feet.

Let us find find the each side length of pool by taking square root of 81 as:

$\text{Each side of square}=\sqrt{81\text{ ft}^2}$

$\text{Each side of square}=9\text{ ft}$

We have been given that girl adds a patio which is 3 feet wide around the pool, so each side of pool after adding patio will increase by 6 feet.

So new sides of pool would be $9\text{ ft}+6\text{ ft}=15\text{ ft}$

The total area of the pool and patio would be product of each side.

$\text{Total area of the pool and patio combined}=15\text{ ft}\times 15\text{ ft}$

$\text{Total area of the pool and patio combined}=225\text{ ft}^2$

Therefore, the total area of the pool and patio combined would be 225 square ft.

5 0

3 years ago

Compute the following 5/9+1/4

n200080 [17]

Answer:

29/36

Step-by-step explanation:

5/9 + 1/4

The common denominator is 36

5/9 *4/4 = 20/36

1/4*9/9 = 9/36

20/36 + 9/36 = 29/36

3 0

3 years ago

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Two faces of a six-sided die are painted red, two are painted blue, and two are painted yellow. The die is rolled three times, a

Keith_Richards [23]

Answer:

(a) 4/9

(b) 19/27

Step-by-step explanation:

The probability of each die turning up red or not turning red are:

$P(R) =\frac{2}{6}= \frac{1}{3}\\P(O) =\frac{4}{6}= \frac{2}{3}$

(a). Exactly one face up is red.

The odds of only the first die being red are:

$P(A=R) =\frac{1}{3} *\frac{2}{3}* \frac{2}{3} \\P(1=R) =\frac{4}{27}$

The same odds are valid for only the second or only the third die being red. Therefore, the probability that exactly one die turns up red is:

$P(R=1) = 3*\frac{4}{27}\\P(R=1) = \frac{4}{9}$

(b). At least one face up is red.

The probability that at least one die turns up red is the sum of the probabilities of exactly one (found in the previous item), two or all dice turning up red.

Following the same logic as in the previous item, the probability that exactly two dice turn up red is:

$P(R=2) = 3*(\frac{1}{3}*\frac{1}{3}*\frac{2}{3})\\P(R=2) = \frac{2}{9}$

The probability that all die turn up red is:

$P(R=3) = \frac{1}{3}*\frac{1}{3}*\frac{1}{3}\\P(R=3)=\frac{1}{27}$

Thus, the probability that at least one die turns up red is:

$P= P(R=1)+P(R=2)+P(R=3) = \frac{4}{9}+\frac{2}{9}+\frac{1}{27}\\P=\frac{19}{27}$

4 0

3 years ago

X + 16 at X= 4<br> 20<br> 21<br> 15

Colt1911 [192]

Answer:

The answer would be 20

Step-by-step explanation:

16+4=20

4 0

3 years ago

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Five-hundred sixty two divided by seven

ladessa [460]

Five hundred and sixty two divided by seven would be,
=80.28

5 0

3 years ago

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