Harold paid $ 16,632 and $ 38,808 for each of the boats.
Since Harold, a marina manager, purchased two boats, and he then sold the boats, the first at a profit of 40% and the second at a profit of 60%, and the total profit on the sale of the two boats was 54 % and $ 88 704 was the total selling price of the two boat, to determine what did Harold originally pay for each of the two boats the following calculation must be performed:
- 55 x 0.6 + 45 x 0.4 = 51
- 65 x 0.6 + 35 x 0.4 = 53
- 70 x 0.6 + 35 x 0.4 = 54
- 88,704 x 0.7 = 62,092.80
- 160 = 62,092.80
- 100 = X
- 100 x 62,092.80 / 160 = X
- 38.808 = X
- 88,704 x 0.3 = 26,611.20
- 140 = 26,611.20
- 100 = X
- 100 x 26,611.20 / 160 = X
- 16,632 = X
Therefore, Harold paid $ 16,632 and $ 38,808 for each of the boats.
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<span>Y=2/3x+3 so slope = 2/3
</span><span>2x-3y=8
3y = 2x - 8
y = 2/3x - 8/3 so slope = 2/3
both equations have same slope = 2/3
so answer: </span><span>parallel</span>
Answer:
1. infinite
2. none
3.one solution
4.none
5.none
Step-by-step explanation:
Answer:
m = 3.50
Don't let the "f" in front of the m fool you!
Hope this is the answer you're looking for!
Notice that the above sequence is arithmetic because the common difference: d is constant.
d = second term - first term.
= 15 - 9
= 6
The general term of an arithmetic sequence is,
a_{n} =a_{1} +(n-1)d
Where , nth term = 
= First term
and d = common difference.
The given sequence is: 9, 15, 21, ...
Here a_{1} = 9,
d = 6
We need to find the 31st term. So, n = 31.
Next step is to plug in these values in the above formula. Therefore,
= 9 + 30* 6
= 9 + 180
= 189
So, 31st term of this sequence is 189.
Hope this helps you.
