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Ivanshal [37]
3 years ago
8

Evaluate −6 − (−1) a.) -7 b.) 5 c.) -5 d.) 6

Mathematics
2 answers:
brilliants [131]3 years ago
8 0

Answer:

-5

hope this helped!!

bearhunter [10]3 years ago
3 0
Answer:
-5

Steps:
S A O
-6 - (-1)
-6 + (+1)
-6 + 1
-5

S- sign states the same
A- sign changes to addition
O- sign becomes the opposite
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15

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8 - 4y + (-2y) + 5 <br><br><br> What is this answer please tell me
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<em>13 - 6y </em>

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Step-by-step explanation:

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3 years ago
Ray has found that his new car gets 31 miles per gallon on the highwayand 26 miles per gallon in the city. He recently drove 285
Mkey [24]

Answer:

Highway = 155\ miles

City = 130\ miles

Step-by-step explanation:

Given

Highway = 31mi/gallon

City = 26mi/gallon

Total\ Miles = 285

Total\ Gallons = 10

Required

Determine the number of miles driven on the highway and on the city

Represent the gallons used on highway with h and on city with c.

So, we have:

c + h = 10 ---- gallons used

and

31h + 26c = 285 --- distance travelled

In the first equation, make c the subject

c = 10 - h

Substitute 10 - h for c in the second equation

31h + 26c = 285

31h + 26(10 - h) = 285

Open bracket

31h + 260 - 26h = 285

Collect like terms

31h - 26h = 285 - 260

5h = 25

Make h the subject

h = \frac{25}{5}

h = 5

Substitute 5 for h in c = 10 - h

c = 10 - 5

c = 5

If on the highway, he travels 31 miles per gallon, then his distance on the highway is:

Highway = 31 * 5

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If in the highway, he travels 26 miles per gallon, then his distance on the highway is:

City = 26 * 5

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3 years ago
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Answer:

0.73

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