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Shalnov [3]
3 years ago
6

Use the formula h=16t^2 to solve the problem . A diver dives from a cliff that has a height of 86.4 feet. Determine the time of

the dive . Round answer to the nearest tenth of a second
Mathematics
1 answer:
sdas [7]3 years ago
3 0
<span>2.3 seconds. Let's assign the known values to the equation and solve for t. h = 16t^2 86.4 = 16t^2 5.4 = t^2 2.323790008 = t Rounding to the nearest tenth of a second gives 2.3 seconds.</span>
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(x-1)(2x+2)<br> Can you please show all of your work.
Komok [63]

Answer:

2x^2 - 2

Step-by-step explanation:

FOIL:

First outer inner last.

So we take (x-1) and (2x+2) and multiply the two first terms together.

2x^2

Next, we do the two outer terms.

2x^2 + 2x

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2x^2 + 2x - 2x

Then the last two terms in the equation.

2x^2 + 2x - 2x - 2

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8 0
3 years ago
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A film distribution manager calculates that 4% of the films released are flops. If the manager is correct, what is the probabili
Anit [1.1K]

Answer:

9.34%

Step-by-step explanation:

p = 4%, or 0.04

n = Sample size = 667

u = Expected value = n * p = 667 * 0.04 = 26.68

SD = Standard deviation = \sqrt{np(1-p)}  =\sqrt{667*0.04*(1-0.04)} = 5.06

Now, the question is if the manager is correct, what is the probability that the proportion of flops in a sample of 667 released films would be greater than 5%?

This statement implies that the p-vlaue of Z when X = 5% * 667 = 33.35

Since,

Z = (X - u) / SD

We have;

Z = (33.35 - 26.68) / 5.06

Z = 1.32

From the Z-table, the p-value of 1.32 is 0.9066

1 - 0.9066 = 0.0934, or 9.34%

Therefore, the probability that the proportion of flops in a sample of 667 released films would be greater than 5% is 9.34%.

6 0
3 years ago
Explain how to do this plz
AVprozaik [17]
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8 0
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Art [367]

Answer:

5372626

Step-by-step explanation:

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7 0
3 years ago
For the amusement of the guests, some hotels have elevators on the outside of the building. One such hotel is 400 feet high. You
Mariana [72]

9514 1404 393

Answer:

  a.  h(t) = -20t +400

  b.  θ(t) = arctan(2 -2/15t); dθ/dt = -30/(1125 -120t +4t^2)

  c.  15 seconds; 100 ft

Step-by-step explanation:

a. The initial height of the elevator is 400 ft. The rate of change of height is -20 ft/s, so the height equation can be ...

  h(t) = -20t +400

__

b. The tangent of the angle above the line of sight is "opposite"/"adjacent":

  tan(θ) = (h(t) -100)/(150) = -2/15t +2

  θ(t) = arctan(2 -2/15t) . . . . radians

The derivative of the angle function is ...

  dθ/dt = 1/(1+(2 -2/15t)^2)(-2/15)

  dθ/dt = -30/(1125 -120t +4t^2)

__

c. The value of dθ/dt will have a peak where the denominator has a minimum, at t = -(-120)/2(4)) = 15. (The quadratic vertex coordinate is t=-b/(2a).)

The elevator appears to be moving fastest at t=15 seconds.

The height at that time is ...

  h(15) = 400 -20(15) = 100

The elevator appears to be moving fastest when it is at eye level, 100 ft above the ground.

5 0
3 years ago
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