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3 years ago

Please help me fill in the blanks

Mathematics

2 answers:

jeka57 [31]3 years ago

6 0

E is an exponential function with an approximate value of 1.

Lina20 [59]3 years ago

3 0

Hmm let’s see text me

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Plsss help... question from gradients. Will give brainliest

Anuta_ua [19.1K]

Answer:

uwuwhwhwnwjwjwiwieiwiwjwjjejeejjwje

Step-by-step explanation:

euwwuwjw

6 0

3 years ago

Answer. it fast please

mojhsa [17]

Answer:

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}$

Step-by-step explanation:

Given

$(\frac{6}{10})^3 * (\frac{5}{9})^2$

Required

Solve:

$(\frac{6}{10})^3 * (\frac{5}{9})^2$

Simplify 6/10

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = (\frac{3}{5})^3 * (\frac{5}{9})^2$

Express 9 as 3^2

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = (\frac{3}{5})^3 * (\frac{5}{3^2})^2$

Apply law of indices

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3}{5^3}* \frac{5^2}{(3^2)^2}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3}{5^3}* \frac{5^2}{3^4}$

Express as a sing;e fraction

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{3^3*5^2}{5^3*3^4}$

Apply law of indices:

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^{3-2}*3^{4-3}}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5^1*3^1}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{5*3}$

$(\frac{6}{10})^3 * (\frac{5}{9})^2 = \frac{1}{15}$

5 0

2 years ago

Sec(-45) a. sec 45 b. -sec 125 c. sec 125 d. -sec 45

Pachacha [2.7K]

Step-by-step explanation:

you have forgot to put degree

3 0

2 years ago

Write an explict equation of how a computer at 2500$ depricates at the rate of 14% per year

ahrayia [7]

Answer:

V(t) = 2500(0.86)^t where t = the year.

Step-by-step explanation:

Each year the value will be 100 - 14 = 86% ( - 0.86) of the previous year.

6 0

3 years ago

Answers for the 2 boxes please:)

masha68 [24]

Answer:

(5,-5)

Step-by-step explanation:

Eliminate y-term

$(2x + 5x) + ( - 3y + 3y) = 25 + 10 \\ 7x = 35 \\ x = \frac{35}{7} \\ x = 5$

We can eliminate x-term but for this system of equations, eliminating y-term is faster.

Substitute x = 5 in any given equations.

I will choose to substitute in the first equation.

$2x - 3y = 25 \\ 2(5) - 3y = 25 \\ 10 - 3y = 25 \\ 10 - 25 = 3y \\ - 1 5 = 3y \\ 3y = - 15 \\ y = - 5$

Answer Check

Substitute both x-value and y-value in any given equations

$2x - 3y = 25 \\ 2(5) - 3( - 5) = 25 \\ 10 + 15 = 25 \\ 25 = 25$

The equation is true. (It is better to check both the answer for both equation.)

Thus the answer is (5,-5)

6 0

3 years ago