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Simora [160]
3 years ago
8

If you work for an hourly wage, your gross pay is a function of the number of hours that you work. If you earn $8 per hour, comp

lete the following table:
Number of Hours
0
3
5
7
10
12
Gross Pay


If you were to plot the ordered pairs on a set of axes, in which quadrant would the domain and range of the function lie?
a.
8, 16, 24, 32, 40, 48; Quadrant I
b.
0, 24, 40, 56, 80, 96; Quadrant II
c.
8, 16, 24, 32, 40, 48; Quadrant II
d.
0, 24, 40, 56, 80, 96; Quadrant I

Mathematics
2 answers:
Gelneren [198K]3 years ago
6 0
1. Let x be the number of hours that you worked. We know from our problem that your hourly wage is $8,  so your hourly wage will be given by the linear function: y=8x. 
where
f(x) is your gross pay.
x is the number of hours that you worked. 

To complete the table, we just need to evaluate the function at the given hours; in other words, we are going to replace x with the number of hours in our linear function:
y=8(0)=0
y=8(3)=24
y=8(5)=40
y=8(7)=56
y=8(10)=80
y=8(12)=96

We can conclude that yous should fill your table as follows: 
<span>Number of Hours
0
3
5
7
10
12
</span><span>
Gross Pay
0
24
40
56
80
96

2. Remember that the domain of a function are the set of the x-values of the function; the range of a function are the set of y-values of the function. From our previous point, we can infer that the ordered pairs of the function are: (0,0), (3,24), (5,40), (7,56), (10,80), and (12,96). The y-values and hence the range of the function are: 0, 24, 40, 56, 80, 96. Remember that in the quadrant I both the x-coordinates and the y-coordinates are positive. Since all the coordinates of our points are positive, we can conclude that the correct answer is:
</span><span>d. 0, 24, 40, 56, 80, 96; Quadrant I</span>

Doss [256]3 years ago
4 0

Answer:

D is the answer

Step-by-step explanation:

yw :)

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F(x) = 9 − x2, x &lt; 3 x − 3, x ≥ 3
liberstina [14]

The table of the function is;

x      f(x)

1       8

2      5

3      0

4      1

5      2

<h3>What are the output values of the x-variables?</h3>

Given the piecewise functions;

           9 - x²,      x < 3

f(x) = {

          x - 3,       x ≥ 3  

For x = 1, since 1 is less than 3, we use the piece of the function under x<3

f(x) = 9 - x²

f(1) = 9 - (1)²

f(1) = 9 - 1

f(1) = 8

Hence, we have a point ( 1,8 )

For x = 2, since 2 is less than 3, we use the piece of the function under x<3

f(x) = 9 - x²

f(2) = 9 - (2)²

f(2) = 9 - 4

f(2) = 5

Hence, we have a point ( 2,5 )

For x = 3, since 3 is greater than or equal to 3, we use the piece of the function under x≥3

f(x) =  x - 3

f(3) =  (3) - 3

f(3) = 3 - 3

f(3) = 0

Hence, we have a point ( 3,0 )

For x = 4, since 4 is greater than 3, we use the piece of the function under x≥3

f(x) =  x - 3

f(4) =  (4) - 3

f(4) = 4 - 3

f(4) = 1

Hence, we have a point ( 4,1 )

For x = 5, since 5 is greater than 3, we use the piece of the function under x≥3

f(x) =  x - 3

f(5) =  (5) - 3

f(5) = 5 - 3

f(5) = 2

Hence, we have a point ( 3,2 )

Therefore, the table of the function is;

x      f(x)

1       8

2      5

3      0

4      1

5      2

Learn more about piecewise functions here: brainly.com/question/12561612

#SPJ1

4 0
2 years ago
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