Answer:
0
Step-by-step explanation:
The only two numbers that would make the whole expression divisible by 8 are 0 and 8. Since the number also has to be divisible by 5, though, the last digit must be a 0 or a 5. Therefore, A=0. Hope this helps!
Answer:
18
Step-by-step explanation:
to be 18 7 bitween one is the complet the neme of soit and can be instracttion
Lol, I'm just answering that question right now. I haven't turned it in yet, but I believe the answer is true as all the sides of an equilateral triangle are equal.
Answer:
Distance B = 1275 kilometers.
Step-by-step explanation:
Let the two distances and time be A and B respectively.
Given the following data;
Distance A = 17 kilometers.
Time A = 8 minutes.
Distance B =?
Time B = 60 minutes.
First of all, we would find the constant speed;
Speed = distance/time
Substituting into the equation, we have;
Speed = 17/8
Speed = 2.125 km/m
Now, to find the distance B;
Distance B = speed * time
Distance B = 2.125 * 60
<em>Distance B = 1275 km</em>
The dimensions of the house should be 7 m by 13 m.
If the house is to be centered, we will take the same amount from the width as we do from the length of the lot for the dimensions. This gives us (10-x) and (16-x) as the dimensions.
The area of a rectangle is found by multiplying the length and width:
(10-x)(16-x) = 91
Multiplying the binomials we have:
10*16 - x*10 - x*16 -x*(-x) = 91
160 - 10x - 16x --x² = 91
160-10x-16x+x² =91
Combine like terms:
160-26x+x²=91
Rewrite this in standard form:
x²-26x+160=91
Subtract 91 from both sides:
x²-26x+160-91 = 91-91
x²-26x+69 = 0
Factoring this, we look for factors of 69 that sum to -26. -23*-3 = 69 and -23+-3 = -26, so:
(x-23)(x-3) = 0
Using the zero product property we know that either x-23=0 or x-3=0, so x=23 or x=3.
x was the amount we take off of the width and length of the lot; if we took 23m off of it, 10-23 gives us a negative amount, which is not realistic. This means both the width and length are subtracted by 3.
10-3 = 7 and 16-3 = 13.
These are the dimensions of the house.
