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Fantom [35]
3 years ago
10

PLEASE HELP ME!!!! PLEASE PLEASE!!! 40 POINTS a rectangular toy box has a length of x + 1 feet a width of 2x - 5 feet if the vol

ume is 90 cubic feet what are the dimensions of the toy box
Mathematics
1 answer:
insens350 [35]3 years ago
5 0

Answer:

the dimensions of the toy box:

Step-by-step explanation:

x+1=2x

2x-5

90

like terms;

- crossing over becomes + and vice versa

soo 2x-2x +90-5

2x^2 cancels it self out leaving 90-5

=85.

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2 because I am correct
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A painter leans a 13ft ladder against a house. The base of the ladder is 5ft from the house. How high on the house does the ladd
lakkis [162]

Answer:

13,92838827718412‬ft

Step-by-step explanation:

a² + b² = c²

a = 13ft

b = 5ft

169 + 25 = 194

c = √194

c = 13,92838827718412‬ft

6 0
4 years ago
The pizza parlor is running a special on 3-toppings pizzas. The topping choices include pepperoni, sausage, bacon mushrooms, oni
choli [55]

Answer:

Well there are 6 toppings. For one person to select sausage, it is  \frac{1}{6} . For two people, multiply them together and the probability is  \frac{1}{36}

4 0
3 years ago
Find the solutions of the quadratic equation 14x^2+9x+10=014x
Vesnalui [34]

Answer:

Option B. x=-\frac{9}{28}(+/-)\frac{\sqrt{479}}{28}i

Step-by-step explanation:

we know that

The formula to solve a quadratic equation of the form ax^{2} +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem we have

14x^{2}+9x+10=0

so

a=14\\b=9\\c=10

substitute in the formula

x=\frac{-9(+/-)\sqrt{9^{2}-4(14)(10)}} {2(14)}

x=\frac{-9(+/-)\sqrt{-479}} {28}

Remember that

i=\sqrt{-1}

substitute

x=\frac{-9(+/-)\sqrt{479}i} {28}  

x=-\frac{9}{28}(+/-)\frac{\sqrt{479}}{28}i

5 0
3 years ago
Give the domain, range, intercepts, asymptotes, intervals of increasing and decreasing, intervals of positive and negative, symm
klemol [59]
y = \frac{3}{x^{2} - 4} + 1

Domain: x² - 4 ≠ 0
                 + 4 + 4
                    x² ≠ 4
                 √x² ≠ √4
                    x ≠ ±2
           x ≠ -2 and x ≠ 2
     (-∞, -2) ∨ (-2, 2) ∨ (2, ∞)

Range: y ≠ 1
    (-∞, 1) ∨ (1, ∞)

Intervals: Increasing: (0.25 , ∞)
              Decreasing: (-∞, 0.25)

Symmetry: X-axis: Not Symmetric
                  Y-axis: Not Symmetric
                  Origin: Not Symmteric

Extrema: Maximum Relative: x = 0
                Minimum Relative: Nothing
3 0
3 years ago
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