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3 years ago

The numbers I circled in red is the questions I have to do can somebody help meh wit dis.Pls and ty .

Mathematics

1 answer:

bija089 [108]3 years ago

4 0

8. 6m + 3n
11. 8r^3 - r^2
12. 3h^2 + 8

hope this helps !

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Does anyone know this and can help please

adelina 88 [10]

Answer:

$\frac{y^7z^3}{x}$

Step-by-step explanation:

When variables have negative exponents, switch their positions.

$\frac{x^{-1}y^7}{z^{-3}}=\frac{y^7z^3}{x}$

5 0

2 years ago

The situation is as follows: Smart phones have changed the world and how we spend our time. A group of researchers at BYU want t

Scilla [17]

Answer:

The 96% confidence interval estimate for the mean daily number of minutes that BYU students spend on their phones in fall 2019 is between 306.65 minutes and 317.35 minutes.

Step-by-step explanation:

Confidence interval normal

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.96}{2} = 0.02$

Now, we have to find z in the Ztable as such z has a pvalue of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.02 = 0.98$ , so Z = 2.054.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 2.054\frac{54}{\sqrt{430}} = 5.35$

The lower end of the interval is the sample mean subtracted by M. So it is 312 - 5.35 = 306.65 minutes

The upper end of the interval is the sample mean added to M. So it is 312 + 5.35 = 317.35 minutes

The 96% confidence interval estimate for the mean daily number of minutes that BYU students spend on their phones in fall 2019 is between 306.65 minutes and 317.35 minutes.

8 0

2 years ago

What is the answer to 15% of 18Kg

Maurinko [17]

Answer:

27/10, or 2 7/10 kg

Step-by-step explanation:

We first have the expression 15/100*18, which simplifies to 3/20*18. If we multiply and simplify, we get 27/10, or 2 7/10

7 0

2 years ago

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