Find the area of the SHADED region. Round to the nearest TENTH if necessary.

Cindy dissolves 19 1 /4 grams of drink mix in 1 3 /4 ounces of water. What is the unit rate in grams of drink mix per ounce of w

Korolek [52]

Answer:

Unit rate in grams of drink mix per ounce of water = 11 gram / ounces

Step-by-step explanation:

Given:

Amount of drink mix = 19 (1 /4) gram = 19.25 gram

Amount of water = 1 (3 /4) ounces = 1.75 ounces

Find:

Unit rate in grams of drink mix per ounce of water = ?

Computation:

⇒ Unit rate in grams of drink mix per ounce of water = Amount of drink mix / Amount of water

⇒ Unit rate in grams of drink mix per ounce of water = 19.25 / 1.75

⇒ Unit rate in grams of drink mix per ounce of water = 11 gram / ounces

5 0

3 years ago

What is AB to the nearest meter

sashaice [31]

Answer:

C. 15

Step-by-step explanation:

Small triangle is similar to larger one so we can use the similarity ratio to solve the question:

CE/CA = DE/AB

4/12 = 5/AB cross multiply expressions

4AB = 60 divide both sides by 4

AB = 15

6 0

3 years ago

Read 2 more answers

A single tree produces about 2.6 × 10² lb of oxygen each year. The Amazon rainforest has about 3.9 X 10^11 trees.

Ymorist [56]

$(2.6\times10^2) \times (3.9\times10^{11}) = 1.014\times10^{14}$

$1.014\times10^{14}$ <---How much is produced by all the trees in a year.
They want how much each day so divide by 365

$\frac{1.014\times10^{14}}{365} = 2.77808\times10^{11}$
$2.77808\times10^{11}$ <---answer per day

6 0

3 years ago

Read 2 more answers

Solve for -6+3x=x-2+4x

Iteru [2.4K]

Answer:

x= -2

Step-by-step explanation: If you feel skeptical about my answer, then you should plug -2 back into the equation to check if it's correct. And it's correct for me when I did it.

7 0

3 years ago

Ksju [112]

Answer:

We conclude that the mean contents of cola bottles is more than or equal to the advertised 300 ml.

Step-by-step explanation:

We are given that Bottles of a popular cola drink are supposed to contain 300 ml of cola. The distribution of the contents is normal with standard deviation of 3 ml.

A student who suspects that the bottler is under-filling measures the contents of six bottles. The results are: 299.4, 297.7, 301.0, 298.9, 300.2, 297.0

Let $\mu$ = mean contents of cola bottles.

SO, Null Hypothesis, $H_0$ : $\mu \geq$ 300 ml {means that the mean contents of cola bottles is more than or equal to the advertised 300 ml}

Alternate Hypothesis, $H_A$ : $\mu$ < 300 ml {means that the mean contents of cola bottles is less than the advertised 300 ml}

The test statistics that will be used here is One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean contents of cola bottle = $\frac{\sum X}{n}$ = 299.03 ml

$\sigma$ = population standard deviation = 3 ml

n = sample of bottles = 6

So, test statistics = $\frac{299.03-300}{\frac{3}{\sqrt{6} } }$

= -0.792

Now at 5% significance level, the z table gives critical value of -1.6449 for left-tailed test. Since our test statistics is more than the critical value of z as -0.792 > -1.6449, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean contents of cola bottles is more than or equal to the advertised 300 ml.

8 0

3 years ago