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lozanna [386]
3 years ago
10

Find the area of the SHADED region. Round to the nearest TENTH if necessary.

Mathematics
1 answer:
lisov135 [29]3 years ago
6 0
The area of the shaded region is 49.2.
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Cindy dissolves 19 1 /4 grams of drink mix in 1 3 /4 ounces of water. What is the unit rate in grams of drink mix per ounce of w
Korolek [52]

Answer:

Unit rate in grams of drink mix per ounce of water = 11 gram / ounces

Step-by-step explanation:

Given:

Amount of drink mix = 19 (1 /4) gram = 19.25 gram

Amount of water = 1 (3 /4) ounces = 1.75 ounces

Find:

Unit rate in grams of drink mix per ounce of water = ?

Computation:

⇒  Unit rate in grams of drink mix per ounce of water = Amount of drink mix / Amount of water

⇒  Unit rate in grams of drink mix per ounce of water = 19.25 / 1.75

⇒  Unit rate in grams of drink mix per ounce of water = 11 gram / ounces

5 0
3 years ago
What is AB to the nearest meter
sashaice [31]

Answer:

C. 15

Step-by-step explanation:

Small triangle is similar to larger one so we can use the similarity ratio to solve the question:

CE/CA = DE/AB

4/12 = 5/AB cross multiply expressions

4AB = 60 divide both sides by 4

AB = 15

6 0
3 years ago
Read 2 more answers
A single tree produces about 2.6 × 10² lb of oxygen each year. The Amazon rainforest has about 3.9 X 10^11 trees.
Ymorist [56]
(2.6\times10^2) \times (3.9\times10^{11}) = 1.014\times10^{14}

1.014\times10^{14} <---How much is produced by all the trees in a year. 
They want how much each day so divide by 365


\frac{1.014\times10^{14}}{365} = 2.77808\times10^{11}
2.77808\times10^{11} <---answer per day

6 0
3 years ago
Read 2 more answers
Solve for -6+3x=x-2+4x
Iteru [2.4K]

Answer:

x= -2

Step-by-step explanation: If you feel skeptical about my answer, then you should plug -2 back into the equation to check if it's correct. And it's correct for me when I did it.

7 0
3 years ago
Bottles of a popular cola drink are supposed to contain 300 ml of cola. There is some variation from bottle to bottle because th
Ksju [112]

Answer:

We conclude that the mean contents of cola bottles is more than or equal to the advertised 300 ml.

Step-by-step explanation:

We are given that Bottles of a popular cola drink are supposed to contain 300 ml of cola. The distribution of the contents is normal with standard deviation of 3 ml.

A student who suspects that the bottler is under-filling measures the contents of six bottles. The results are: 299.4, 297.7, 301.0, 298.9, 300.2, 297.0

<u><em>Let </em></u>\mu<u><em> = mean contents of cola bottles.</em></u>

SO, Null Hypothesis, H_0 : \mu \geq  300 ml   {means that the mean contents of cola bottles is more than or equal to the advertised 300 ml}

Alternate Hypothesis, H_A : \mu < 300 ml   {means that the mean contents of cola bottles is less than the advertised 300 ml}

The test statistics that will be used here is <u>One-sample z test statistics</u> as we know about the population standard deviation;

                       T.S.  = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample mean contents of cola bottle = \frac{\sum X}{n} = 299.03 ml

            \sigma = population standard deviation = 3 ml

            n = sample of bottles = 6

So, <em><u>test statistics</u></em>  =  \frac{299.03-300}{\frac{3}{\sqrt{6} } }     

                               =  -0.792

<em>Now at 5% significance level, the z table gives critical value of -1.6449 for left-tailed test. Since our test statistics is more than the critical value of z as -0.792 > -1.6449, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.</em>

Therefore, we conclude that the mean contents of cola bottles is more than or equal to the advertised 300 ml.

8 0
3 years ago
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