W + 19 = 49 for w = 30 :
30 + 19 = 49
hope this helps !.
the center is at the origin of a coordinate system and the foci are on the y-axis, then the foci are symmetric about the origin.
The hyperbola focus F1 is 46 feet above the vertex of the parabola and the hyperbola focus F2 is 6 ft above the parabola's vertex. Then the distance F1F2 is 46-6=40 ft.
In terms of hyperbola, F1F2=2c, c=20.
The vertex of the hyperba is 2 ft below focus F1, then in terms of hyperbola c-a=2 and a=c-2=18 ft.
Use formula c^2=a^2+b^2c
2
=a
2
+b
2
to find b:
\begin{gathered} (20)^2=(18)^2+b^2,\\ b^2=400-324=76 \end{gathered}
(20)
2
=(18)
2
+b
2
,
b
2
=400−324=76
.
The branches of hyperbola go in y-direction, so the equation of hyperbola is
\dfrac{y^2}{b^2}- \dfrac{x^2}{a^2}=1
b
2
y
2
−
a
2
x
2
=1 .
Substitute a and b:
\dfrac{y^2}{76}- \dfrac{x^2}{324}=1
76
y
2
−
324
x
2
=1 .
Answer:
The amount that plant earns per man hour after (t) years it open is $80 
.
Step-by-step explanation:
Given as :
The earning of manufacturing plant when it opened = $ 80 per man hour
The rate of plant earning per man hour = 5 %
Let The earning of plant after t years = A( t )
So,
The earning of plant after t years = initial earning × 
Or, A(t) = $ 80 × 
or, A(t) = $ 80 ×
Hence The amount that plant earns per man hour after (t) years it open is $80 . Answer
