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vivado [14]
2 years ago
5

What are the challenges of similar triangles?

Mathematics
1 answer:
Lady bird [3.3K]2 years ago
6 0

Answer:

There are two types of similar triangle problems; these are problems that require you to prove whether a given set of triangles are similar and those that require you to calculate the missing angles and side lengths of similar triangles. Subtract both sides by 130°. Hence; By Angle-Angle (AA) rule, ΔPQR~ΔXYZ.

Step-by-step explanation:

You might be interested in
Find the volume of a 2by2​
STALIN [3.7K]

Answer:

24

Step-by-step explanation:

2+2+2 = 6*2 = 12*2 = 24

3 0
2 years ago
The average of your first 6 tests is 82. If your test average after your seventh test is an 80.5, what did you score on the seve
mart [117]
So average is  of the first 6 tests is 82   well that means 

(test1 + test2+ test3+ test4 + test5+test6)/6 = 82

so now let do some cross multiplliying 

test1 + test2 + test3 + test 4 + test5 +test6 = 82*6

test1 + test2 + test3 + test 4 + test5 +test6  = 492

now lets see if we can find that 7th test score

(test1 + test2 + test3 + test4 + test5 +test6 + test7)/7 = 80.5

So look we found test1 + test2 + test3 + test4 + test5 +test6 to be 492 so lets substitute. 

(492 + test7 )/7 = 80.5

test7 = (80.5*7)-492 = 71.5 



7 0
3 years ago
Multiply<br> (4n - 5)(2n + 5)
likoan [24]

Answer:

8n^2+10n-25

Step-by-step explanation:

it's probably wrong that's what I got tough xp

4 0
3 years ago
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Diano4ka-milaya [45]

Answer:

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7 0
2 years ago
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According to class 8 please solve
-Dominant- [34]

Answer:

i) The value of x is 3.

ii) TE = 20cm

RN = 20cm

Step-by-step explanation:

According to the properties of rectangles,

The diagonals of rectangles are equal and bisect each other at 90°.

As per this,

OR = OT

2x + 4 = 3x + 1

4 - 1 = 3x - 2x

3 = x

TE = 2OT

TE = 2(3x + 1)

= 6x + 2

= 6(3) + 2

= 18 + 2

= 20

RN = 2OR

RN = 2(2x + 4)

= 4x + 8

= 4(3) + 8

= 12 + 8

= 20

6 0
2 years ago
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