Answer:
length = 10 units; width = 3 units
Step-by-step explanation:
Let the width = w
Then the length is w + 7
Original area: w(w + 7)
Double the width: 2w
Increase the length by 2: w + 9
Area of new rectangle: 2w(w + 9)
Area of new rectangle = w(w + 7) + 42
2w(w + 9) = w(w + 7) + 42
2w^2 + 18w = w^2 + 7w + 42
w^2 + 11w - 42 = 0
(w + 14)(w - 3) = 0
w + 14 = 0 or w - 3 = 0
w = -14 or w = 3
A width cannot be negative, so we discard w = -14.
The original width is 3 units.
The length is 7 more than the width, so the length is 10 units.
The area of a rectangle is <em>L x W</em>. We have to get the value of x first so that we can find the area of the rectangle.
To get the value of x
given:
<span>a. 12 & X
b. X-2 & 16 </span>
solution:
12x (x) = (8-2 ) 16
12x = 16x-32
32 = 16x-- 12x
<u>32 </u> = <u>4x</u>
4 4
8 = x
Checking:
a. 12 & X b. X-2 & 16
Area of a rectangle = L x W Area of a rectangle = L x W
=12 x 8 = (8-2) 16
Area of a rectangle = 96 = 6 (16)
Area of a rectangle = 96
This can made the answer
<span>1.2, 5.6, 3.5, 7.8, 9.0</span>
$65=$29+$9
- 29 -29
----------------
36 9x
---------------
9 9
X=4
Answer:
we have the same computer
Step-by-step explanation:
