Based on the distance between triangles ABC and A'B'C', the line of reflection that reflects ABC to A'B'C' is (x = 1).
<h3>Where is the line of reflection?</h3>
To find this out, you can use the coordinates of a point in triangle ABC and it's corresponding point in A'B'C'.
The coordinates of B is (3, 2)
The coordinates of B' is (-1, 2)
Find the midpoint between these points:
= ( (x₁ + x₂) / 2), ((y₁ - y₂) /2)
= (( 3 + (-1)) / 2 ) , ((2 - 2) / 2))
= (1, 0)
This shows that the line of reflection is x = 1.
Find out more on the line of reflection at brainly.com/question/1908648
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Answer:
choice 3
Step-by-step explanation:
9/12 simplified = 3/4. 6/8 simplified =3/4
so they are the same
The mean of these numbers would be 1. you get this be adding up all the numbers, then dividing it by how many numbers there are.
-21 + 17 +15 +-25 +19 = 5
5/5 = 1
Answer:
c
Step-by-step explanation:
x²+y²+4x+6y=0
compare with x²+y²+2gx+2fy+c=0
centre is (-g,-f)=(-2,-3)
radius=√(g²+f²-c)=√((-2)²+(-3)²-0)=√13
Answer:
add like terms on both sides (3x+6=3x+21
subtract like terms (x+6=21)
subtract like terms (x=15)