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3 years ago

50 pts if you answer plz plz

Mathematics

1 answer:

Nikitich [7]3 years ago

8 0

Answer:

Step-by-step explanation:

Table 1: Add 7 to each output too get the answer for each input. Example output 1 +7 =Output 8

Table 2: Multiply each input by 6 to get the answer for each output. Example input 4 x 6=output 24

Table 3: Add 10 to each input to get output. Example 10+10=20 output

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Using finite difference, the answer is cubic. Apologies if I’m wrong

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2 years ago

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For a given angle θ, sin θ = 1. What is cos θ?

sergiy2304 [10]

Answer:

sin90 =1

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Step-by-step explanation:

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2 years ago

If 1 inch is about 2.54 cm, how many inches are in 16 cm?

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6.299 or 6.3 depending on how it wants you to round

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2 years ago

A vertical right circular cylindrical tank has height h=8 feet high and diameter d=6 feet. It is full of kerosene weighing 50 po

Mariana [72]

Answer:

The work done to pump all of the kerosene from the tank to an outlet is $W=45238.9\: J$

Step-by-step explanation:

The work is defined by:

$W=\int dFdx$ (1)

The force here will be the product between the volume and the kerosene weighing, so we have :

$dF=\pi R^{2}dy*50$

This force will be in-lbs.

Where R is the radius (3 feet)

Then using (1), we have:

$W=\int \pi R^{2}dy*50(8-y)$

Here 8-y is a distance at some point of the tank. Now, to get the work done from the base to the top of the tank we will need to take integral from 0 to 8 feet.

$W=\int_{0}^{8} \pi 3^{2}dy*50(8-y)$

$W=450\pi \int_{0}^{8}dy(8-y)$

$W=450\pi(\int_{0}^{8} 8dy-\int_{0}^{8} ydy)$

$W=450\pi(8y|_{0}^{8} -\frac{y^{2}}{2}|_{0}^{8})$

$W=450\pi(8*8 -\frac{8^{2}}{2})$

$W=450\pi(64 -\frac{64}{2})$

Therefore, the work done to pump all of the kerosene from the tank to an outlet is $W=45238.9\: J$

I hope it helps you!

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2 years ago

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Answer:

$864

Step-by-step explanation:

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2 years ago