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aliya0001 [1]
3 years ago
13

How many solutions does the quadratic system shown below have ?

Mathematics
1 answer:
Anna11 [10]3 years ago
4 0
It is 4! hope this helps>3
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If a > b and b > C, what is true about the
Stella [2.4K]

Answer:

  a > c

Step-by-step explanation:

The Transitive Property of Inequality can be written as ...

  If a > b and b > c, then a > c.

Based on the above, we can conclude from your premises that a > c.

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3 years ago
Which of the following expressions is equivalent to
Pepsi [2]

Answer:

The answer is D).

Step-by-step explanation:

I am assuming that you are talking about exponents and powers. So I assumed that:

A) was 4.325 * 10^-9,

B) was 4.325 * 10^-6,

C) was 4.325 * 10^6,

D) was 4.325 * 10^9

I just went for gusto, and multiplied/solved answer D), and it was correct. I just punched into calculator, and boom. 4,325,000,000. I hope this helps!

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4 years ago
Ethan is buying clothes for a camping trip. A pair of hiking boots costs $96, a flannel shirt costs $33, a pair of shorts costs
Iteru [2.4K]
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3 0
3 years ago
Read 2 more answers
The principal amount, $4200, earns 3.6% interest compounded monthly.
svlad2 [7]

Answer:

a)

A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}

b)

The total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 4,200.00 at a rate of 3.6% per year  compounded 12 times per year  over 10 years is $5667.28.

Step-by-step explanation:

a. Write the function that represents the value of the account at any time, t.

The function that represents the value of the account at any time, t

A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}

where

P represents the principal amount

r represents Annual Rate

n represents the number of compounding periods per unit t, at the end of each period

t represents the time Involve

b) What will the value be after 10 years?

Given

The principal amount  P = $4200

Annual Rate r = 3.6% = 3.6/100 = 0.036

Compounded monthly = n = 12

Time Period = t

To Determine:

The total amount A = ?

Using the formula

A\:=\:P\left(1\:+\:\frac{r}{n}\right)^{nt}

substituting the values

A\:=\:4200\left(1\:+\:\frac{0.003}{12}\right)^{\left(12\right)\left(10\right)}

\:A\:=\:4200\left(1.0025\right)^{120}

A=5667.28 $

Therefore, the total amount accrued, principal plus interest,  from compound interest on an original principal of  $ 4,200.00 at a rate of 3.6% per year  compounded 12 times per year  over 10 years is $5667.28.

6 0
3 years ago
6=u/9.6<br> What does U=?
uranmaximum [27]

Answer:

U=57.6

Step-by-step explanation:

8 0
3 years ago
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