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DedPeter [7]
3 years ago
7

Find the value of x.

Mathematics
2 answers:
Talja [164]3 years ago
7 0

Answer:

x=19

Step-by-step explanation:

you do 180-123 because angles on a straight line add up to 180

this gives you 57

then you divide this answer by 3 which gives you the answer of x

masha68 [24]3 years ago
6 0
171 because first u minus 180 from 123 then you times that by 3
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Question 21 is probably the hardest question on this homework
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Anyone can help me solve this equation using cross multiplying
Natali5045456 [20]

9514 1404 393

Answer:

  x = 1 or 5

Step-by-step explanation:

The notion of "cross-multiplying" is the idea that the numerator on the left is multiplied by the denominator on the right, and the numerator on the right is multiplied by the denominator on the left. This looks like ...

  \displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\ \longrightarrow\ (x-1)(3x-1)=(7)(2x-2)

Then the solution proceeds by eliminating parentheses, and solving the resulting quadratic equation.

  3x^2-4x+1=14x-14\\\\3x^2-18x+15=0\qquad\text{subtract $14x-14$}\\\\x^2-6x+5=0 \qquad\text{divide by 3}\\\\(x-1)(x-5)=0\qquad\text{factor}\\\\x\in\{1,5\}

_____

<em>Comment on "cross multiply"</em>

Like a lot of instructions in Algebra courses, the idea of "cross multiply" describes <em>what the result looks like</em>. It doesn't adequately describe how you get there. The <em>one and only rule</em> in solving Algebra problems is "<em>whatever is done to one side of the equation must also be done to the other side of the equation</em>." If you multiply one side by one thing and the other side by a different thing, you are violating this rule.

What looks like "cross multiply" is really "<em>multiply by the product of the denominators</em> and cancel like terms from numerator and denominator." Here's what that looks like with the intermediate steps added.

  \displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\\\\\frac{x-1}{7}\times7(3x-1)=\frac{2x-2}{3x-1}\times7(3x-1)\\\\(x-1)(3x-1)=(2x-2)(7)\qquad\textit{looks like}\text{ cross multiply}

8 0
2 years ago
The tile along the edge of a triangular community pool needs to be replaced. A right triangles, where the hypotenuse is labeled
jolli1 [7]

Perimeter of a closed figure is the sum of length of its outline. The perimeter of the consider triangular pool is: 12x^2 + 8x + 25 units.

<h3>How to calculate perimeter of a triangular figure?</h3>

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For the given case, we have:

Length of first side(hypotenuse) = 8x^2 units

Height = 4x^2 + 15 units

Base is of length 8x + 10

Thus, its perimeter is calculated as:

Perimeter of a triangle = Sum of lengths of all its 3 sides.

Perimeter =  8x^2 + 4x^2 + 15 + 8x + 10 = (8+4)x^2 + 8x + 25 = 12x^2 + 8x + 25 units

Perimeter = 12x^2 + 8x + 25 units

Thus,

The perimeter of the consider triangular pool is: 12x^2 + 8x + 25 units.

Learn more about perimeter here:

brainly.com/question/10466285

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