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3 years ago

12

A and B are complementary angles. If mA=(x+8)° and mB =(8x+1), find the measure of A

1 answer:

Black_prince [1.1K]3 years ago

4 0

Answer:

$\angle A=17\textdegree$

Step-by-step explanation:

We know that A and B are complementary angles. So, they must add up to 90°. As an equation:

$\angle A+\angle B=90$

Since we know their equations, substitute:

$(x+8)+(8x+1)=90$

Solve for x. Combine like terms on the left:

$9x+9=90$

Subtract 9 from both sides:

$9x=81$

Divide both sides by 9:

$x=9$

So, the value of x is 9.

We want to find A. So, let's use the equation for A:

$\angle A=x+8$

Substitute 9 for x:

$\angle A=9+8$

Add:

$\angle A=17\textdegree$

So, the measure of A is 17°.

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Solve the following inequality for y.<br> 18x + 6y > 12

Murljashka [212]

Answer:

12

Step-by-step explanation:

Simplifying

18x + -6y = 12

Solving

18x + -6y = 12

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '6y' to each side of the equation.

18x + -6y + 6y = 12 + 6y

Combine like terms: -6y + 6y = 0

18x + 0 = 12 + 6y

18x = 12 + 6y

Divide each side by '18'.

x = 0.6666666667 + 0.3333333333y

Simplifying

x = 0.6666666667 + 0.3333333333y

3 0

3 years ago

Will give u 20 points brainlist

Vitek1552 [10]

Answer:

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Step-by-step explanation:

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2 years ago

Which expressions have the same value as .04 x .005. Select all that apply.

Novay_Z [31]

Answer:

Hello There!!

Step-by-step explanation:

0.04×0.005=0.0002

.0002 ✔

(4/100)=>0.04 × (5/1000)=>0.005=0.0002 ✔

(4 × .01)=>0.04 × (5 × .001)=>0.0005 =0.00002 ❌

.002 ❌

4 × 5 × .00001=0.0002 ✔

hope this helps,have a great day!!

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4 0

3 years ago

what is the point-slope form of the equation of the line passing through the points (–6, –4) and (2, –5).

ioda

Answer:

The equation of the line would be y + 4 = -1/8(x + 6)

Step-by-step explanation:

To find the point-slope form of the line, start by finding the slope. You can do this using the slope formula below along with the two points.

m(slope) = (y2 - y1)/(x2 - x1)

m = (-4 - -5)/(-6 - 2)

m = 1/-8

m = -1/8

Now that we have the slope, we can use that along with one of the points in the base form of point-slope.

y - y1 = m(x - x1)

y + 4 = -1/8(x + 6)

7 0

3 years ago

Please solve 5 f <br> (Trigonometric Equations)<br> #salute u if u solved it

Zanzabum

Answer:

$\beta=45\degree\:\:or\:\:\beta=135\degree$

Step-by-step explanation:

We want to solve $\tan \beta \sec \beta=\sqrt{2}$ , where $0\le \beta \le360\degree$ .

We rewrite in terms of sine and cosine.

$\frac{\sin \beta}{\cos \beta} \cdot \frac{1}{\cos \beta} =\sqrt{2}$

$\frac{\sin \beta}{\cos^2\beta}=\sqrt{2}$

Use the Pythagorean identity: $\cos^2\beta=1-\sin^2\beta$ .

$\frac{\sin \beta}{1-\sin^2\beta}=\sqrt{2}$

$\implies \sin \beta=\sqrt{2}(1-\sin^2\beta)$

$\implies \sin \beta=\sqrt{2}-\sqrt{2}\sin^2\beta$

$\implies \sqrt{2}\sin^2\beta+\sin \beta- \sqrt{2}=0$

This is a quadratic equation in $\sin \beta$ .

By the quadratic formula, we have:

$\sin \beta=\frac{-1\pm \sqrt{1^2-4(\sqrt{2})(-\sqrt{2} ) } }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm \sqrt{1^2+4(2) } }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm \sqrt{9} }{2\cdot \sqrt{2} }$

$\sin \beta=\frac{-1\pm3}{2\cdot \sqrt{2} }$

$\sin \beta=\frac{2}{2\cdot \sqrt{2} }$ or $\sin \beta=\frac{-4}{2\cdot \sqrt{2} }$

$\sin \beta=\frac{1}{\sqrt{2} }$ or $\sin \beta=-\frac{2}{\sqrt{2} }$

$\sin \beta=\frac{\sqrt{2}}{2}$ or $\sin \beta=-\sqrt{2}$

When $\sin \beta=\frac{\sqrt{2}}{2}$ , $\beta=\sin ^{-1}(\frac{\sqrt{2} }{2} )$

$\implies \beta=45\degree\:\:or\:\:\beta=135\degree$ on the interval $0\le \beta \le360\degree$ .

When $\sin \beta=-\sqrt{2}$ , $\beta$ is not defined because $-1\le \sin \beta \le1$

4 0

3 years ago