Write down the multiples of each number vertically and horizontally

Round 0.293263 to the ten thousandths place

gladu [14]

Answer:

0.293263 rounded to the ten thousandths place

=0.2933

5 0

2 years ago

Read 2 more answers

Factorise fully 6x - 8

Amanda [17]

Answer:

2(3x+ 4)

I hope it helps

Pls mark as brainliest

3 0

3 years ago

Read 2 more answers

Encuentre el resultado de la diferencia de las fracciones: 9 /12 - 2/3=

Veronika [31]

Responder:

1/12

Explicación paso a paso:

Entonces multiplicamos 9 por 3 y obtenemos 27.

Luego multiplicamos 2 por 12 y obtenemos 24.

A continuación, le damos a ambos términos nuevos denominadores: 12 × 3 = 36.

Así que ahora nuestras fracciones se ven así:

27

36

-

24

36

Paso 2

Dado que nuestros denominadores coinciden, podemos restar los numeradores.

27 - 24 = 3

Entonces la respuesta es:

3

36

Paso 3

Por último, necesitamos simplificar la fracción, si es posible. ¿Se puede reducir a una fracción más simple?

Para averiguarlo, intentamos dividirlo por 2 ...

¡No! Así que ahora probamos con el siguiente número primo mayor, 3 ...

¿Son tanto el numerador como el denominador divisibles por 3? ¡Sí! Entonces lo reducimos:

3

36

÷ 3 =

1/12

8 0

3 years ago

Do you tailgate the car in front of you? About 35% of all drivers will tailgate before passing, thinking they can make the car i

Vesna [10]

Answer:

(a) The histogram is shown below.

(b) E (X) = 4.2

(c) SD (X) = 2.73

Step-by-step explanation:

Let X = r = a driver will tailgate the car in front of him before passing.

The probability that a driver will tailgate the car in front of him before passing is, P (X) = p = 0.35.

The sample selected is of size n = 12.

The random variable X follows a Binomial distribution with parameters n = 12 and p = 0.35.

The probability function of a binomial random variable is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x}$

(a)

For X = 0 the probability is:

$P(X=0)={12\choose 0}(0.35)^{0}(1-0.35)^{12-0}=0.006$

For X = 1 the probability is:

$P(X=1)={12\choose 1}(0.35)^{1}(1-0.35)^{12-1}=0.037$

For X = 2 the probability is:

$P(X=2)={12\choose 2}(0.35)^{2}(1-0.35)^{12-2}=0.109$

Similarly the remaining probabilities will be computed.

The probability distribution table is shown below.

The histogram is also shown below.

(b)

The expected value of a Binomial distribution is:

$E(X)=np$

The expected number of vehicles out of 12 that will tailgate is:

$E(X)=np=12\times0.35=4.2$

Thus, the expected number of vehicles out of 12 that will tailgate is 4.2.

(c)

The standard deviation of a Binomial distribution is:

$SD(X)=np(1-p)$

The standard deviation of vehicles out of 12 that will tailgate is:

$SD(X)=np(1-p)=12\times0.35\times(1-0.35)=2.73\\$

Thus, the standard deviation of vehicles out of 12 that will tailgate is 2.73.

4 0

3 years ago

Question 7 of 15 Which is an equation of the line through (0,0) and (5,-2)? O A. y = 3 B. y = ja c. y = - 30 D. y=- Y

9966 [12]

Answer:

b po sana po maka tulong

Step-by-step explanation:

pa brainliest po

6 0

2 years ago