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3 years ago

Which situation can be represented by 3s = 5s - 6 ?

Mathematics

1 answer:

grin007 [14]3 years ago

8 0

Answer:

First one

Step-by-step explanation:

3s=5s-6

You might be interested in

Maria's book is longer than Brandon's. The difference in the two book lengths is 56

Bingel [31]

Answer:

Maria's book is 202 pages long, Brandon's book is 146 pages long

Step-by-step explanation:

We can set this up with 2 variables: lets say that Maria's book length is x and Brandon's is y.

We can see that Maria's book is 56 pages longer than Brandon's and can come up with an equation:

x=y+56

We also see that their booklengths add up to 348, and can get:

x+y=348

From here, we solve for x and y. We can use substitution to find y.

x+y=348

(y+56)+y=348

2y=292

y=146

Here we plug in for x:

x=y+56

x=(146)+56

x=202

Therefor we get that Maria's book is 202 pages long, Brandon's book is 146 pages long

7 0

2 years ago

Find the value of pq - r/4 when p= -8 and q= -3 and r= 68

andrey2020 [161]

Answer:

Step-by-step explanation:

pq - r/4

(-8)(-3) - 68/4

-8 x -3 = 24 (2 negatives equal a positive)

24 - 68/4

68/4 = 17

24-17 = 7

6 0

3 years ago

Dana is playing a game where she loses 75 points every time she rolls an even number. She starts with 0 points. Then she rolls a

slavikrds [6]

Answer:

-375

Step-by-step explanation:

-75 * 5

= -375.

3 0

3 years ago

Can anyone help ?\me with this algebra answer

sleet_krkn [62]

The first one is correct

3 0

3 years ago

Read 2 more answers

Problem PageQuestion Calcium levels in people are normally distributed with a mean of mg/dL and a standard deviation of mg/dL. I

SIZIF [17.4K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The calcium level that is the borderline between low calcium levels and those not considered low is $c = 8.68$

Step-by-step explanation:

From the question we are told that

The mean is $\mu = 9.5\ mg/dL$

The standard deviation $\sigma = 0.5 \ mg/dL$

The proportion of the population with low calcium level is $p =$ 5% = 0.05

Let X be a X random calcium level

Now the P(X < c) = 0.05

Here P denotes probability

c is population with calcium level at the borderline

Since the calcium level is normally distributed the z-value is evaluated as

$P(Z < \frac{c - \mu}{\sigma } ) = 0.05$

The critical value for 0.05 from the standard normal distribution table is

$t_{0.05} = -1.645$

=> $\frac{c - \mu}{\sigma } = -1.645$

substituting values

$\frac{c - 9.5}{0.5 } = -1.645$

=> $c - 9.5 = -0.8225$

=> $c = 8.68$

6 0

3 years ago