Answer:
a. a = 1, b = -5, c = -14
b. a = 1, b = -6, c = 9
c. a = -1, b = -1, c = -3
d. a = 1, b = 0, c = -1
e. a = 1, b = 0, c = -3
Step-by-step explanation:
a. x-ints at 7 and -2
this means that our quadratic equation must factor to:
FOIL:
Simplify:
a = 1, b = -5, c = -14
b. one x-int at 3
this means that the equation will factor to:
FOIL:
Simplify:
a = 1, b = -6, c = 9
c. no x-int and negative y must be less than 0
This means that our vertex must be below the x-axis and our parabola must point down
There are many equations for this, but one could be:
a = -1, b = -1, c = -3
d. one positive x-int, one negative x-int
We can use any x-intercepts, so let's just use -1 and 1
The equation will factor to:
This is a perfect square
FOIL:
a = 1, b = 0, c = -1
e. x-int at 
our equation will factor to:
This is also a perfect square
FOIL and you will get:
a = 1, b = 0, c = -3
Answer:
Step-by-step explanation:
to make it quick
2*110 = arc FI
220° = arc FI
arc LI = 97°
arc FL = x
360 = 220 + 97 + x
43 = X
arc FL = 43°
:)
A vertical line that the graph of a function approaches but never intersects. The correct option is B.
<h3>When do we get vertical asymptote for a function?</h3>
Suppose that we have the function f(x) such that it is continuous for all input values < a or > a and have got the values of f(x) going to infinity or -ve infinity (from either side of x = a) as x goes near a, and is not defined at x = a, then at that point, there can be constructed a vertical line x = a and it will be called as vertical asymptote for f(x) at x = a
A vertical asymptote can be described as a vertical line that the graph of a function approaches but never intersects.
Hence, the correct option is B.
Learn more about Vertical Asymptotes:
brainly.com/question/2513623
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Point-slope form of a line: We need a point (x₀,y₀) and the slope "m";
y-y₀=m(x-x₀)
We have the next equation of line:
y=1/2 x-2 (slope-intercept form y=mx+b)
the slope of this line is 1/2 (m=1/2)
And any one point could be:
if x=0; then y=1/2 (0)-2=-2 (0,-2)
Therefore, we already have the point (0-,2) and the slope (m=1/2)
y-y₀=m(x-x₀)
y+2=1/2(x-0)
Answer: the point slope form of y=1/2 x-2; would be:
y+2=1/2(x-0)
Answer:
f(-3)= - (-3)+5= +3 +5 = 8
