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2 years ago

Write three sets of Pythagorean triplets such that each set has numbers less than 30

Mathematics

1 answer:

AlexFokin [52]2 years ago

7 0

Answer:

The three sets of Pythagorean triplets such that each set has numbers less than 30 are 3, 4 and 5; 6, 8 and 10; 5, 12 and 13

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

First I found the equation of the line.

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X^2 - y^2 = 100

luda_lava [24]

Answer:

Step-by-step explanation:

Let's start by rewriting the second equation in terms of "x":

$x+y=5$

Subtract y from both sides:

$x=5-y$

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$(5-y)^2-y^2=100$

Note that:

$(a-b)^2=a^2-2ab+b^2$

$25-10y+y^2-y^2=100$

Cancel out like terms:

$25-10y=100$

Subtract 25 from both sides:

$-10y=75$

Divide both sides by -10

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Now, substitute this value back into either of the equations to solve for x.

$x+y=5\\x-\frac{15}{2}=5\\$

Add 15/2 to both sides:

$x=5+\frac{15}{2}\\x=\frac{10}{2}+\frac{15}{2}\\x=\frac{25}{2}$

Now, find the difference:

$x-y=\frac{25}{2}-(-\frac{15}{2})=\frac{25}{2}+\frac{15}{2}=\frac{40}{2}=20$

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2 years ago

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Answer:

when 926 is divide by 38 it's remainder is 14.

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3 years ago

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Answer:

the answer to this question is the third bullet

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2 years ago

Write three sets of Pythagorean triplets such that each set has numbers less than 30​

Write three sets of Pythagorean triplets such that each set has numbers less than 30