C: i just answered it and got it right

The identity of an element is determined by its number of

Goryan [66]

Answer:

its atomic number

Explanation:

4 0

3 years ago

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Jackson will be taking his college entrance exam next weekend. Part A Relate each of the following terms to his preparation for

Mnenie [13.5K]

Answer:

The answer is "Glutamate Hippocampus, Frontal lobe, Sympathetic nervous system Cerebellum, and GABA increase the performance during the exam".

Explanation:

The features that contributed himself to prepare successfully also for tests involve glutamate, the hippocampus, and the front lobes, because all of these variables are related to recall, and they know how great memory results throughout the research. Cerebellum, (GABA), a sympathetic nervous and also has a major effect on the output of Jackson the day of the exam since the nervous system sends extra blood to the muscles when stress is occurring whereas the cerebral cortex aids muscles in coordinating which, Requires body function, like writing. Because of stress-free conditions, GABA is taken orally.

8 0

3 years ago

18. If a cell needs to get waste out and nutrients in, this works best if

Dovator [93]

Answer:

We reduce the size of the cell

and increase surface area to volume ratio.

Explanation:

6 0

3 years ago

3.6 In mice, the allele C for colored fur is dominant over the allele c for white fur, and the allele V for normal behavior is d

KengaRu [80]

Answer:

a) Parents Genotype should be (CC,Vv) and (cc,VV).

b) The genotypes of the parents are (Cc,Vv) and (Cc,Vv).

c) The genotypes of the parents are (Cc,Vv) and (cc,vv).

Explanation:

Mating has occured between a normal colored mice whose genotype is C_,V_ and normal white mice with genotype cc,V_. The offsprings are as follows :

1) normal mice produced 29 colored

2) 10 colored, waltzing progeny.

Thus all offspring are normal. The genotype of the first parent should therefore be CC. Waltzing trait is produced. The V gene should therefore be heterozygous in both traits.

Hence The parent genotypes should be<u> (CC,Vv) and (cc,CV).</u>

In this case the approximate ratio in which the descendants are produced is 9:3:3:1. Hence genotypes of the parents are <u>(Cc,Vv) and (Cc,Vv). </u>

In this case the approximate ratio in which the offsprings are produced is 1:1:1. The genotypes of the parents are <u>(Cc,Vv) and (cc,vv). </u>

3 0

3 years ago

If the frequency of one allele in a population is 0. 7 in a population with two alleles at a particular locus, what is the frequ

Kipish [7]

According to Hardy- Weinberg principle, if the frequency of one allele in a population with two alleles is 0.7 at a particular locus, then the frequency of alternate allele is 0.3.

<h3>What is Hardy- Weinberg equilibrium?</h3>

Hardy- Weinberg rule states that in the absence of disturbing factors, the genetic variability in a population remains constant in different generations.
It states that when mating is random both the genotypic and allelic frequencies remain constant as they are in equilibrium.
Hardy- Weinberg rule applies to a large population where mating is random and there is no migration.
It is given by p + q = 1, where p is the frequency of dominant allele in the population, q is the frequency of recessive allele in the population.
By squaring, p2+ 2pq+ q2= 1, where p2 is percentage of homozygous dominant individuals, q2 is percentage of homozygous recessive individuals. 2pq is percentage of heterozygous individuals.
Here given, p= 0.7, therefore q= 1- 0.7= 0.3

Learn more about Hardy- Weinberg equilibrium here:

brainly.com/question/3406634

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8 0

2 years ago