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4 years ago

Writing Trigonometric Ratios -

Mathematics

2 answers:

scoray [572]4 years ago

8 0

Option3 is the answer..!!!

AlexFokin [52]4 years ago

3 0

Hello!

Let's review our trigonometric ratios.

$Sine= \frac{opposite}{hypotenuse}$

$Cosine= \frac{adjacent}{hypotenuse}$

$Tangent=\frac{opposite}{adjacent}$

Let's look which lines are opposite, adjacent, and hypotenuse.

Opposite: XZ

Adjacent: YZ

Hypotenuse: XY

Let's plug these into our ratios.

$SinY= \frac{XZ}{XY}$

$CosY=\frac{YZ}{XY}$

$TanY=\frac{XZ}{YZ}$

As you can see, these numbers match answer C.

I hope this helps!

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PLEASE HELP RIGHT AWAY, <br> THANK U SO MUCH!! <3

vredina [299]

Answer:

1. Ans;

${a}^{7} \times {a}^{12} = {a}^{7 + 12} = {a}^{19}$

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2. Ans;

$\frac{ {h}^{6} }{ {h}^{2} } = {h}^{4}$

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3. Ans;

${e}^{6} \times {e}^{6} = {e}^{6 + 6} = {e}^{12}$

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4.Ans;

$\frac{ {w}^{9} }{ {w} } = {w}^{8}$

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5. Ans;

${g}^{2} \times {h}^{3} \times {g}^{2} \times h = {g}^{2 + 2} \times {h}^{3 + 1} = {g}^{4} {h}^{4}$

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6.Ans;

$\frac{10 {a}^{12} }{ 6{a}^{3} } = \frac{5 {a}^{9} }{3}$

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7.Ans;

$({m}^{4} )^{5} = {m}^{4 \times 5} = {m}^{20}$

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8.Ans;

${(3 {a}^{2} })^{3} = ( {3})^{3} ( {a}^{2} ) ^{3} = 27 {a}^{6}$

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9.Ans;

${( \frac{c}{k} })^{4} = \frac{ {c}^{4} }{ {k}^{4} }$

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10.Ans;

${( \frac{8x}{9} })^{2} = \frac{( {8x})^{2} }{ ({9})^{2} } = \frac{64 {x}^{2} }{81}$

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11.Ans;

$4 {c}^{2} \times {c}^{3} = 4 {c}^{2 + 3} = 4 {c}^{5}$

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12.Ans;

${( - 9 {h}^{4} {k}^{6} })^{2} = {( - 9)}^{2} {( {h}^{4} })^{2} {( {k}^{6} })^{2} = 81 \: \: {h}^{8} {k}^{12}$

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13.Ans;

$( { \frac{2d}{3e} })^{3} = \frac{ {(2d)}^{3} }{ ({3e)}^{3} } = \frac{8 {d}^{3} }{27 {e}^{3} }$

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14. Ans;

${( \frac{4}{ {w}^{5} }) }^{3} = \frac{ ({4)}^{3} }{( {w}^{5} ) ^{3} } = \frac{64}{ {w}^{15} }$

_____o___o_____

$\frac{5 {v}^{4} \times 4 {v}^{5} }{2 {v}^{3} } = \frac{20 {v}^{4 + 5} }{2 {v}^{3} } = \frac{20 {v}^{9} }{2 {v}^{3} } = 10 {v}^{6}$

_o_o_

$( \frac{3 {f}^{4}h}{4 {h}^{9} } ) ^{3} = \frac{( {3})^{3} ( {f}^{4})^{3} ({h})^{3} }{ {(4)}^{3} ( {h}^{9})^{3} } \\ \\ \\ = \frac{27 {f}^{4 \times 3} {h}^{3} }{64 {h}^{9 \times 3} } = \frac{27 {f}^{12} {h}^{3} }{64 {h}^{27} } \\ \\ \\ = \frac{27 {f}^{12} }{64 {h}^{24} }$

I hope I helped you^_^

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never [62]

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Katena32 [7]

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a. debemos buscar la cantidad de repuesto donde el valor no sea haga negativo, por lo tanto debe ser un numero que al cuadrado no sea mayor que 32, pero sea el que más se encuentre cerca.

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